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11th Standard English Medium Computer Science Subject Flow of Control Creative 3 Mark Questions with Solution Part - II

Published on: 29/06/2021

QB365 provides detailed and simple solution for every Creative Questions in class 11 Computer Science Subject. It will helps to get more idea about question pattern in every Creative questions with solution.

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Std: 11th Standard - Computer Science

chapter: - Creative Questions

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Questions:

Generic 3

5 x 3 = 15

What is do-while loop? Write it's syntax.

Write the syntax of nested ·switch statement.

Differentiate break and continue statement.

Write a C++ program to find sum of any 5 numbers.

Write C++ program to sum the numbers from 1 to 10 using for loop.

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Answers Key:

Generic 3

5 x 3 = 15

The do-while loop is an exit-controlled loop. In do-while loop, the condition is evaluated at the bottom of the loop after executing the body of the loop. This means that the body of the loop is executed at least once, even when the condition evaluates false during the first iteration.
The do-while loop. syntax is:
do
{
Body of the loop;
} while (condition);

The syntax of the nested switch statement is;
switch (expression)
{
case constant 1:
statement(s);
break;
switch( expression)
{
case constant 1:
statement (s);
break;
case constant 2:
statement(s);
break
.
.
.
default :
statement(s);
}
case constant 2:
statement(s);
break;
.
.
.
default:
statement( );
}

Break	Continue
The break is used to terminate the execution of the loop	Continue is not used to terminate the execution of the loop.
It breaks the iteration	It skips the iteration
When this statement is executed, control will come out from the loop and execute the the statement immediately after the loop.	When this statement is executed, it will not come out of the loop but moves/jumps to the next iteration of the loop.
The break is used with loops as well as switch cases.	Continue is only used in loops, it is not used in switch cases.

#include< iostream.h >
using namespace std;
int main ( )
{
int i=1,num,avg,sum=0;
while(i < =5)
{
cout << "Enter the number :";
cin>>num;
sum=sum+num;
i++;
}
avg=sum/5;
cout << "The sum is" << sum << endl;
return 0;
}
Output
Enter the number: 1
Enter the number: 2
Enter the number: 3
Enter the number: 4
Enter the number: 5
The sum is 15

#include < iostream.h >
using namespace std;
int main ( )
{
int i, sum=0;
for(i=l; i < =10; i++)
{
sum=sum + i;
}
cout << "The sum of 1 to 10 is" << sum;
return 0;
}
Output
The sum of 1 to 10 is 55