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11th Standard English Medium Physics Subject Kinetic Theory of Gases Creative 2 Mark Questions with Solution Part - I updated Creative Questions

Published on: 13/05/2022

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Std: 11th Standard - Physics

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Questions:

Generic 2

5 x 2 = 10

Define most probable speed of the gas. Write its expressions.

Define Average speed. Write it equation.

Define Avogadro's number.

Define root mean square speed (v_rms). Write down its equations.

What is Degree of freedom?

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Answers Key:

Generic 2

5 x 2 = 10

It is defined as the speed acquired by most of the molecules of the gas.
\({ V }_{ mp }=\sqrt { \cfrac { 2RT }{ M } } =\sqrt { \cfrac { 2KT }{ m } } =1.41\sqrt { \cfrac { kT }{ m } } \)

Average speed is defined as the mean (or) average of all the speeds of molecules
\(\bar { v } =\cfrac { { v }_{ 1 }+{ v }_{ 2 }+{ v }_{ 3 }+...+{ v }_{ n } }{ n } =\sqrt { \cfrac { 8RT }{ \pi m } } =\sqrt { \cfrac { 8kT }{ \pi } } =1.41\sqrt { \cfrac { KT }{ m } } \)

It is defined as the number of particles present in one mole of the substance. It is denoted by N_A·
N_A= 6.0225\(\times\)10²³mol^-1

Root mean square speed is defined as the square root of the mean of the square of speeds of all molecules. It is denoted by \({ v }_{ rms }=\sqrt { \bar { { v }^{ 2 } } } \)
Mean square speed \(\bar { { v }_{ 2 } } =\cfrac { 3kT }{ m } \)
\(\therefore { v }_{ rms }=\sqrt { \cfrac { 3kT }{ m } } =1.73\sqrt { \cfrac { kT }{ m } } \)

The degree of freedom for a dynamic system is the number of directions in which it can move freely of the number of coordinates required to describe completely the position and configuration of the system. It is denoted by for N.