Voltage V = (100 ± 5)V
Current I = (10 ± 0.2)A
Resistance R = ?
Then resistance R is given by Ohm's law,
\(R={V\over I}={100\over 10}=10\Omega\)
\({\triangle R\over R}=({\triangle V\over V}+{\triangle I\over I})\)
\({\triangle R\over R}=({\triangle V\over V}+{\triangle I\over I})R=({5\over 100}+{0.2\over 10})10\)
= (0.05 + 0.02)10 = 0.07\(\times\)10 = 0.7
The resistance R = (10 ± 0.7)\(\Omega\)

(b/t) should have the dimensions of velocity
b has the dimensions of (velocity x time) .
[b] = [LT^-1][T] = [L] = [M⁰L¹T⁰]

Life of the man = 100 years
100 years includes 76 normal years and 24 leap years
Total no of days = 76\(\times\)365 + 24\(\times\)366 = 36524 days
Number of seconds = 36524\(\times\)24\(\times\)3600 = 3.155\(\times\)10° second
\(\text{Number of hearts beats}=\frac{Total\ no\ of\ seconds}{Time\ period\ of\ heart\ beat}=\frac{3.155\times10^9}{0.8s}=3.94\times10^9\)

Let, \(Q={{x^2y^3}\over{z^1}}.\)
It is given, \({{Δx}\over{x}}=2\%{{Δy}\over{y}}=3\%{{Δz}\over{z}}=1\%\)
\({{ΔQ}\over{Q}}=2\left( {{Δx}\over{x}} \right)+3\left( {{Δy}\over{y}} \right)+1\left( {{Δz}\over{z}} \right)\)
= 2(2%) + 3(3%) + 1(1%)
\({{ΔQ}\over{Q}}=4\%+9\%+1\%=14\%\)

Dimension for distance s = [L]
Dimension for initial velocity v= [LT^-1]
Dimension for time t = [T]
Dimension for acceleration a = [LT^-2]
According to the principle of homogeneity,
Dimensions of LHS = Dimensions of RHS
Substituting the dimensions in the given formula
S = ut + 1/4 at², \(\frac{1}{4}\) is a number. It has no dimension
[L] = [LT^-1][T¹] + [LT^-2][T²]
[L] = [L] + [L]
As the dimensional formula of LHS is same as that of RHS, the equation is dimensionally correct.
Comment:
But actually it is a wrong equation. We know that the equation of motion is
s = ut +1/2 at²
So, a dimensionally correct equation need not be the true (or) actual equation. But a true equation is always dimensionally correct.