11th Standard Syllabus & Materials

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Tamilnadu 11th Standard Tamil மொழி கலை -செய்யுள் - ஒவ்வொரு புல்லையும் Important Questions And Answers Study Material - QB365

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11th Standard

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11th Standard

Tamilnadu 11th Standard Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set B

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Tamilnadu 11th Standard Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set B

11th Standard English Medium Physics Subject Oscillations Book Back 1 Mark Questions with Solution Part - II

Published on: 07/06/2021

QB365 provides detailed and simple solution for every Book back Questions in class 11 Physics Subject. It will helps to get more idea about question pattern in every book back questions with solution.

Download Tamil Nadu 11th Standard Physics question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

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Std: 11th Standard - Physics

chapter: - Book back Questions

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Questions:

Multiple Choice Question

5 x 1 = 5

A hollow sphere is filled with water. It is hung by a long thread. As the water flows out of a hole at the bottom, the period of oscillation will

(a)

first increase and then decrease

(b)

first decrease and then increase

(c)

increase continuously

(d)

decrease continuously

An ideal spring of spring constant k, is suspended from the ceiling of a room and a block of mass M is fastened to its lower end. If the block is released when the spring is un-stretched, then the maximum extension in the spring is

(a)

4\(\frac { Mg }{ k } \)

(b)

\(\frac { Mg }{ k } \)

(c)

2\(\frac { Mg }{ k } \)

(d)

\(\frac { Mg }{ 2k } \)

Two bodies A and B whose masses are in the ratio 1:2 are suspended from two separate massless springs of force constants k_A and k_B respectively. If the two bodies oscillate vertically such that their maximum velocities are in the ratio 1:2, the ratio of the amplitude A to that of B is

(a)

\(\sqrt { \frac { { K }_{ B } }{ { 2 }K_{ A } } } \)

(b)

\(\sqrt { \frac { { K }_{ B } }{ { 8 }K_{ A } } } \)

(c)

\(\sqrt { \frac { {2 K }_{ B } }{ { }K_{ A } } } \)

(d)

\(\sqrt { \frac { {8 K }_{ B } }{ { }K_{ A } } } \)

The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on surface of planet X such that the acceleration of the planet X is n times greater than the Earth is

(a)

0.9n

(b)

\(\frac{0.9}{n}\)m

(c)

0.9n²m

(d)

\(\frac{0.9}{n^2}\)

In a simple harmonic oscillation, the acceleration against displacement for one complete oscillation will be

(a)

an ellipse

(b)

a circle

(c)

a parabola

(d)

a straight line

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Answers Key:

Multiple Choice Question

5 x 1 = 5

Initially when the sphere in completely filled with water, its centre of gravity (C.G) lies at its centre. As water flows out, the centre of gravity begins to shift below the centre of the sphere. The effective length of the pendulum increases and hence the time period increases. When the sphere is half empty C.G begins to rise up. As the length of pendulum decreases T decreases.

\(\mathrm{F} =-\mathrm{kx} \)
\(\therefore \mathrm{x} =\left|-\frac{F}{k^{\prime}}\right|=\frac{F}{k^{\prime}} \)
\(\mathrm{F} =\mathrm{Mg} \text { and } k^{\prime}=\frac{k}{2} \)
\(\therefore \mathrm{x} =\frac{M g}{\frac{k}{2}} \)
\(=\frac{2 M g}{k} \)

\(\mathrm{V}_{\mathrm{A}}: \mathrm{V}_{\mathrm{B}} =1: 2 \)
\(\mathrm{~A}_{\mathrm{A}}: \mathrm{A}_{\mathrm{B}} =\sqrt{k_{B}}: \sqrt{8 k_{A}} \)
\(=\sqrt{\frac{k_{B}}{8 k_{A}}} \)

\(l =0.9 \)
\(\mathrm{~T} =2 \pi \frac{l}{g} \)
\(T^{\prime} =2 \pi \frac{l_{X}}{g_{X}} \)
\(\mathrm{~g} \mathrm{x} =\mathrm{ng} \)
\(\therefore \mathrm{x} =0.9 \mathrm{n} \)

The sketch between cause (magnitude of acceleration) and effect (magnitude of displacement) is a straight line.