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11th Standard English Medium Physics Subject Waves Book Back 1 Mark Questions with Solution Part - II

Published on: 07/06/2021

QB365 provides detailed and simple solution for every Book back Questions in class 11 Physics Subject. It will helps to get more idea about question pattern in every book back questions with solution.

Download Tamil Nadu 11th Standard Physics question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

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Std: 11th Standard - Physics

chapter: - Book back Questions

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Questions:

Multiple Choice Question

5 x 1 = 5

Which of the following represents a wave

(a)

(x - vt)³

(b)

x(x+vt)

(c)

\(\frac{1}{x+vt}\)

(d)

sin(x+vt)

The displacement y of a wave travelling in the x direction is given by y = (2\(\times\)10 ^-3) sin (300t - 2x + \(\frac{\pi}{4}\)), where x and y are measured in metres and t in second. The speed of the wave is

(a)

150 ms^-1

(b)

300 ms^-1

(c)

450 ms^-1

(d)

600 ms^-1

A person standing between two parallel hills fires a gun and hears the first echo after t₁ sec and the second echo after t₂ sec. The distance between the two hills is

(a)

\(\frac { v({ t }_{ 1 }-{ t }_{ 2 }) }{ 2 } \)

(b)

\(\frac { v\left( { t }_{ 1 }{ t }_{ 2 } \right) }{ 2({ t }_{ 1 }+{ t }_{ 2 }) } \)

(c)

v (t₁+ t₂)

(d)

\(\frac { v({ t }_{ 1 }+{ t }_{ 2 }) }{ 2 } \)

Compare the velocities of the wave forms given below, and choose the correct option.

where, v_A, v_B, v_C and v_D are velocities given in (A), (B), (C) and (D), respectively.

(a)

v_A > v_B > v_D > v_C

(b)

v_A< v_B < v_D < v_C

(c)

v_A = v_B = v_D = v_C

(d)

v_A > v_B = v_D > v_C

For a particular tube, among six harmonic frequencies below 1000 Hz, only four harmonic frequencies are given: 300 Hz, 600 Hz, 750 Hz and 900 Hz. What are the two other frequencies missing from this list?

(a)

100 Hz, 150 Hz

(b)

150 Hz, 450 Hz

(c)

450 Hz, 700 Hz

(d)

700 Hz, 800 Hz

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Answers Key:

Multiple Choice Question

5 x 1 = 5

(d)
sin(x+vt)

The given equation is similar to
\(\mathrm{y} =\mathrm{A} \sin \left(\omega t-\frac{x}{\lambda}\right) \)
\(\omega=300, \ \mathrm{f} =\frac{300}{2 \pi}=\frac{150}{\pi} \)
\(\text { Speed } \mathrm{v} =\mathrm{f} \lambda \)
\(=\frac{150}{\pi} \times \pi \)
\(=150 \mathrm{~ms}^{-1} \)

\(2 d_{1}=v t_{1}-\text { first echo }\)
\(2 d_{2}=v t_{2}-\text { second echo }\)
\(\therefore \mathrm{d}=\mathrm{d}_{1}+\mathrm{d}_{2} \quad \therefore \frac{v\left(t_{1}+t_{2}\right)}{2}\)

The amplitude of the velocity wave is same in all four cases

\(\mathrm{f}_{\mathrm{o}}=150 \mathrm{~Hz}\)
\(\text { From the series of frequencies is }\)
\(f_{1} =2 f_{0} \)
\(f_{2} =3 f_{0} \)
\(=3 \times 150=450 \mathrm{~Hz} \)