11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil இயற்கை வேளாண்மை,சுற்றுச்சூழல் -செய்யுள் - மனோன்மணீயம் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil என்னுயிர் என்பேன் -துணைப்பாடம் - இசைத்தமிழர் இருவர் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil மொழி கலை -செய்யுள் - ஒவ்வொரு புல்லையும் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - இலக்கணம் - பகுபத உறுப்புகள் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - துணைப்பாடம் - வாடிவாசல் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set A

Published on: 10/11/2020
11th Standard Physics Oscillations English Medium Free Online Test One Mark Questions 2020 - 2021
Download Tamil Nadu 11th Standard Physics question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Physics Test1.
A particle is executing SHM. Then the graph of velocity as a function of displacement is _______.
straight line
circle
ellipse
hyperbola
2.
In order to double the period of a simple pendulum _______.
its length should doubled
its length should be quadrupled
the mass of its bob should be doubled
the mass of its bob should be quadrupled.
3.
A small body of mass 50 g is undergoing SHM of amplitude 100 cm and period 0.2 s. What is the maximum value of the force acting on the body?
86.4 N
98.5 N
102.1 N
71.2 N
4.
The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with S.H.M with an angular frequency of 200 rad/min. Then the maximum speed will be _________.
50 m/min
100 m/min
150 m/min
200 m/min
5.
A particle executing a SHM has a maximum displacement of 2 cm its acceleration at a distance of 0.5 cm from its mean position is 2 cm/s2, What will be its velocity when it is at a distance of 1 cm from its mean position?
4 cm/s
2\(\sqrt{3}\)
11.2 cm/s
4\(\sqrt{7}\)
6.
The three springs with force constant \({ k }_{ 1 }=7.5\frac { N }{ m } ,{ k }_{ 2 }=10.0\frac { N }{ m } ,{ k }_{ 3 }=12.5\frac { N }{ m } \), are connected in parallel to a mass of 0.500 kg. The mass is then pulled to the right and released. Then the period of the motion is _______________.
0.6s
0.8s
0.5 s
004 s
7.
Find the length of a simple pendulum whose period is 2.00 s _______________.
2 m
0.4 m
0.1 m
3 m
8.
The magnitude of acceleration of particle executing SHM at the position of maximum displacement is ____________.
zero
minimum
maxmium
none of these
9.
What is time period of a pendulum hanged in a satellite? (T is time period on earth)
zero
T
infinite
\(\frac { T }{ \sqrt { 6 } } \)
10.
A particle is executing SHM at mid point of mean position & extermity. What is the potential energy in terms of total energy (E) _______________.
\(\frac{E}{4}\)
\(\frac{E}{16}\)
\(\frac{E}{2}\)
\(\frac{C}{8}\)
11.
A particle executing simple harmonic motion along y-axis has its motion described by the equation y = A.sin (ωt) + B, the amplitude of the example harmonic motion is ______________.
A
B
A+B
\(\sqrt{A+B}\)
12.
The man velocity of a particle, executing simple harmonic motion with an amplitude 7 mm is 4.4 m s-1. The period of oscillation is ________________.
0.01s
0.1s
10s
100s
13.
The simple harmonic motions are respresented by the equation. y1 = 0.1 sin (100πt + π/3) & Y2= 0.1 cos π the phase difference of the velocity of particle is _________________.
-\(\frac { \pi }{ 6 } \)
\(\frac { \pi }{ 3 } \)
-\(\frac { \pi }{ 6 } \)
\(\frac { \pi }{ 6 } \)
14.
A particle excites simple harmonic motion between x = -A & x = +A, the time taken for it to go from 0 to \(\frac{A}{2}\) is T1 & to go from \(\frac{A}{2}\) to A is T2 then _______________.
T1
T1>T2
T1=T2
T1=2T2
15.
When a damped harmonic oscillator completes 100 oscillations, its amplitude is reduced to \(\frac{1}{3}\) of its initial value. What will be its amplitude when it completes 200 oscillations?
\(\frac{1}{5}\)
\(\frac{2}{3}\)
\(\frac{1}{6}\)
\(\frac{1}{9}\)
16.
A hollow sphere is filled with water. It is hung by a long thread. As the water flows out of a hole at the bottom, the period of oscillation will
first increase and then decrease
first decrease and then increase
increase continuously
decrease continuously
17.
An ideal spring of spring constant k, is suspended from the ceiling of a room and a block of mass M is fastened to its lower end. If the block is released when the spring is un-stretched, then the maximum extension in the spring is
4\(\frac { Mg }{ k } \)
\(\frac { Mg }{ k } \)
2\(\frac { Mg }{ k } \)
\(\frac { Mg }{ 2k } \)
18.
The time period for small vertical oscillations of block of mass m when the masses of the pulleys are negligible and spring constant k1 and k2 is

\(T=4\pi \sqrt { m\left( \frac { 1 }{ { k }_{ 1 } } +\frac { 1 }{ { k }_{ 2 } } \right) } \)
\(T=2\pi \sqrt { m\left( \frac { 1 }{ { k }_{ 1 } } +\frac { 1 }{ { k }_{ 2 } } \right) } \)
\(T=4\pi \sqrt { m\left( { k }_{ 1 }+{ k }_{ 2 } \right) } \)
\(T=2\pi \sqrt { m\left( { k }_{ 1 }+{ k }_{ 2 } \right) } \)
19.
The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on surface of planet X such that the acceleration of the planet X is n times greater than the Earth is
0.9n
\(\frac{0.9}{n}\)m
0.9n2m
\(\frac{0.9}{n^2}\)
20.
In a simple harmonic oscillation, the acceleration against displacement for one complete oscillation will be
an ellipse
a circle
a parabola
a straight line
1.
(c)
ellipse
2.
(b)
its length should be quadrupled
3.
(b)
98.5 N
4.
(b)
100 m/min
5.
(b)
2\(\sqrt{3}\)
6.
(b)
0.8s
7.
(c)
0.1 m
8.
(c)
maxmium
9.
(c)
infinite
10.
(a)
\(\frac{E}{4}\)
11.
(a)
A
12.
(a)
0.01s
13.
(a)
-\(\frac { \pi }{ 6 } \)
14.
(a)
T1
15.
Amplitude at any instant is given by
\(a=a_{0} e^{-b t}\)
\(\mathrm{a}_{0}=\text { initial amplitude }\)
b = damping constant
Case 1:
\(t =100 \mathrm{~T} \)
\(a =\frac{a_{0}}{3} \)
\(\therefore \frac{a_{0}}{3} =a_{0} e^{-b 100 T} \)
\(e^{-b 100 T}=\frac{1}{3}\) ....(1)
Case 2:
\(a=a_{0} e^{-200 b T} \)
\(a=a_{0}^{(-100 b T) 2} e=a_{0}\left(\frac{1}{3}\right)^{2} \)
\(a=\frac{a_{0}}{9} \)
16.
Initially when the sphere in completely filled with water, its centre of gravity (C.G) lies at its centre. As water flows out, the centre of gravity begins to shift below the centre of the sphere. The effective length of the pendulum increases and hence the time period increases. When the sphere is half empty C.G begins to rise up. As the length of pendulum decreases T decreases.
17.
\(\mathrm{F} =-\mathrm{kx} \)
\(\therefore \mathrm{x} =\left|-\frac{F}{k^{\prime}}\right|=\frac{F}{k^{\prime}} \)
\(\mathrm{F} =\mathrm{Mg} \text { and } k^{\prime}=\frac{k}{2} \)
\(\therefore \mathrm{x} =\frac{M g}{\frac{k}{2}} \)
\(=\frac{2 M g}{k} \)
18.
\(\mathrm{T}=2 \pi \sqrt{\frac{m}{k}}\)
The given arrangement is similar to the combination of springs in series
\(\therefore \frac{1}{k}=\frac{1}{k_{1}}+\frac{1}{k_{2}} \)
\(\therefore T^{\prime}=2 \pi \sqrt{m\left(\frac{1}{k_{1}}+\frac{1}{k_{2}}\right)} \)
19.
\(l =0.9 \)
\(\mathrm{~T} =2 \pi \frac{l}{g} \)
\(T^{\prime} =2 \pi \frac{l_{X}}{g_{X}} \)
\(\mathrm{~g} \mathrm{x} =\mathrm{ng} \)
\(\therefore \mathrm{x} =0.9 \mathrm{n} \)
20.
The sketch between cause (magnitude of acceleration) and effect (magnitude of displacement) is a straight line.
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil பீடு பெற நில் - உரைநடை - மலை இடப்பெயர்கள் : ஓர் ஆய்வு Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - துணைப்பாடம் - யானை டாக்டர் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - செய்யுள் - ஐங்குறுநூறு Important Questions And Answers Study Material - QB365 Set A
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