11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil இயற்கை வேளாண்மை,சுற்றுச்சூழல் -செய்யுள் - மனோன்மணீயம் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil என்னுயிர் என்பேன் -துணைப்பாடம் - இசைத்தமிழர் இருவர் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மொழி கலை -செய்யுள் - ஒவ்வொரு புல்லையும் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - இலக்கணம் - பகுபத உறுப்புகள் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - துணைப்பாடம் - வாடிவாசல் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set A
Published on: 10/11/2020
11th Standard Physics Oscillations English Medium Free Online Test One Mark Questions with Answer Key 2020 - 2021
Download Tamil Nadu 11th Standard Physics question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Physics Test1.
The three springs with force constant \({ k }_{ 1 }=8\frac { N }{ m } ,{ k }_{ 2 }=10\frac { N }{ m } ,{ k }_{ 3 }=12\frac { N }{ m } \), are connected in series to a mass of 0.500. The mass is then pulled to the right and released. Then the period of the motion is ________________.
2s
2.2s
2.5s
3.1s
2.
A pendulum 1.20 m long is observer to have 1 m Long is observed to have a period of 2.00 s at a certain location then the acceleration due to gravity is _______________.
9.71 m/s2
9.85 m/s2
9.79 m/s2
10.1 m/s2
3.
Find the period of a simple pendulum 1.20 m long _____________.
1.4 s
3.2 s
4.1 s
2.2 s
4.
Two simple pendulums of time periods 2.0 s & 2.1 s are made to vibrate simultaneously. They are in phase initially, after how may vibrations are there in the same phase?
21
25
30
35
5.
The phase difference between the unstantaneous velocity & acceleration of a particle executing simple harmonic motion is ________________.
0.5 π
π
0.707π
0.61 m
6.
If a simple pendulum of length 'L' has maximum angular displacement. Then the maximum kinetic energy of bob mass m is ____________.
\(\frac { 1 }{ 2 } \frac { ML }{ 9 } \)
\(\frac { Mg }{ 2L } \)
MgL (1- cos α)
MgL sinα/2
7.
The ratio of frequences of 2 pendulums are 2 : 3, then their lengths are in ratio ______________.
\(\sqrt { \frac { 2 }{ 3 } } \)
\(\sqrt { \frac { 3 }{ 2 } } \)
\(\frac{4}{9}\)
\(\frac{9}{4}\)
8.
A spring is cut into 4-equal parts & 2 parts are connected in parallel. What is the effective in parallel. What is the effective spring contest?
4 k
16 k
8 k
6 k
9.
When the maximum k.E of a simple pendulum is k, then what is its displacement in terms of amplitude a when its K.E. is k/2 ____________.
a/\(\sqrt{2}\)
a/2
a/\(\sqrt{3}\)
a/3
10.
If x, v & a denote the displacement, the velocity & acceleration of a particle executing simple harmonic motion of time period T, then which of the following does not change with time ____________.
a2t2+4π2v2
aT/x
aT+2πv
aT/v
11.
The displacement of an object attached to a spring & executing SAM is given by x = 2\(\times\)10-2 cos πt the time at which the speed first occus is ________________.
0.55 μ
0.75 μ
0.125 μ
0.25 μ
12.
The function x =Asin2ωt + B cos2ωt + c sin rot cos rot represents simple harmonic motion for which of the option?
for all values of A, B & C (C# 0) (b) \(\frac{r}{10}\)
A=B, C = 2B
CA = -B, C = 2B
all of the above
13.
The x-t graph of a particle undergoing simple harmonic motion is shown. The acceleration of the particle at t =\(\frac{4}{3}\) is ______________.
\(\frac { \sqrt { 3 } }{ 32 } \pi \) cm/s2
\(\frac { -{ \pi }^{ 2 } }{ 32 } \) cm/s2
\(\frac { { \pi }^{ 2 } }{ 32 } \) cm/s2
\(\frac { -\sqrt { 3 } }{ 32 } \)
14.
A particle executes simple harmonic motion and displacement y at time t0, 2t0 and 3t0 are A, B and C, respectively. Then the value of \(\frac{A+C}{2B}\) is
cos ωt0
cos 2ωt0
cos 3ωt0
1
15.
The damping force on an oscillator is directly proportional to the velocity. The units of the constant of proportionality are
kgms−1
kgms−2
kgs−1
kgs
16.
17.
A simple pendulum has a time period T1. When its point of suspension is moved vertically upwards according as y = k t2, where y is vertical distance covered and k = 1 ms−2, its time period becomes T2. Then, \(\frac { { T }_{ 1 }^{ 2 } }{ { T }_{ 2 }^{ 2 } } \) is (g = 10 m s−2).
\(\frac{5}{6}\)
\(\frac{11}{10}\)
\(\frac{6}{5}\)
\(\frac{5}{4}\)
18.
A spring is connected to a mass m suspended from it and its time period for vertical oscillation is T. The spring is now cut into two equal halves and the same mass is suspended from one of the halves. The period of vertical oscillation is
T'= \(\sqrt{2}\)T
\(T'=\frac { T }{ \sqrt { 2 } } \)
T'=\(\sqrt{2T}\)
\(T'=\sqrt { \frac { T }{ 2 } } \)
19.
A simple pendulum is suspended from the roof of a school bus which moves in a horizontal direction with an acceleration a, then the time period is
\(T\propto \frac { 1 }{ { g }^{ 2 }+{ a }^{ 2 } } \)
\(T\propto \frac { 1 }{ \sqrt { { g }^{ 2 }+{ a }^{ 2 } } } \)
\(T\propto \sqrt { { g }^{ 2 }+{ a }^{ 2 } } \)
\(T\propto \left( { g }^{ 2 }+{ a }^{ 2 } \right) \)
20.
A particle executing SHM crosses points A and B with the same velocity. Having taken 3 s in passing from A to B, it returns to B after another 3 s. The time period is
15 s
6 s
12 s
9 s
1.
(c)
2.5s
2.
(b)
9.85 m/s2
3.
(d)
2.2 s
4.
(a)
21
5.
(a)
0.5 π
6.
(c)
MgL (1- cos α)
7.
(d)
\(\frac{9}{4}\)
8.
(c)
8 k
9.
(a)
a/\(\sqrt{2}\)
10.
(b)
aT/x
11.
(a)
0.55 μ
12.
(d)
all of the above
13.
(d)
\(\frac { -\sqrt { 3 } }{ 32 } \)
14.
(a)
cos ωt0
15.
\(\mathrm{F}_{\mathrm{d}} \propto \mathrm{v} \)
\(\mathrm{F}_{\mathrm{d}}=-\mathrm{bv} ; \quad \mathrm{F}_{\mathrm{d}}=\mathrm{kv} \)
\(\therefore \mathrm{k}=\frac{F_{d}}{v} \)
\(\text { Units of } k=\frac{k g m s^{-2}}{m s^{-1}}\)
\(\mathrm{k}=\mathrm{kg} \mathrm{s}^{-1}\)
16.
(d)
17.
\(\mathrm{T}= \mathrm{T}_{1}=2 \pi \sqrt{\frac{l}{g}} \)
\(T_{1}^{2}=4 \pi^{2} \frac{l}{g} \)
\(\mathrm{y}=\mathrm{kt}^{2} \quad \mathrm{k}=1 \mathrm{~m} \mathrm{~s}^{-2} \)
\(\therefore \mathrm{y}=\mathrm{t}^{2} \quad \mathrm{y} \propto \mathrm{t}^{2} \)
\(\frac{y_{1}}{y_{2}}=\frac{t_{1}^{2}}{t_{2}^{2}} \)
\(\frac{T_{1}^{2}}{T_{2}^{2}}=\frac{y_{1}}{y_{2}}=\frac{6}{5} \)
18.
\(\mathrm{T}=2 \pi \sqrt{\frac{m}{k}}\)
when the spring is cut into two equal halves, than the force constant of each part is 2k. When the mass is suspended from one of the halves, new time period is \(T^{\prime}=2 \pi \sqrt{\frac{m}{2 k}}=\frac{T}{\sqrt{2}}\)
19.
\(T=2 \pi \sqrt{\frac{\ell}{g}}\)
\(\text { when a bus is moving } g^{\prime} \sqrt{g^{2}+a^{2}}\)
\(\therefore T \propto \frac{1}{\sqrt{g^{2}+a^{2}}}\)
20.
Time period is the time taken by particle is return to B = 4 x 3 = 12s
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil பீடு பெற நில் - உரைநடை - மலை இடப்பெயர்கள் : ஓர் ஆய்வு Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - துணைப்பாடம் - யானை டாக்டர் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - செய்யுள் - ஐங்குறுநூறு Important Questions And Answers Study Material - QB365 Set A
Tamilnadu Stateboard 11th Standard Subjects
Maths
Commerce
Economics
Biology
Business Maths and Statistics
Accountancy
Computer Science
Physics
Chemistry
Maths
Biology
Economics
Physics
Chemistry
History
Business Maths and Statistics
Computer Science
Accountancy
Computer Applications
History
Computer Technology
Commerce
Computer Applications
Computer Technology
Tamil
English
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