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Published on: 24/09/2019
Atoms and Molecules
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1.
Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.(Atomic mass of Al = 27u)
2.
Calculate the molecular masses of H2, O2, Cl2, CO2, CH4, C2H6, NH3, CH3OH
3.
How many grames of Na will have the same number of atoms as in 6 grames of Mg?(Atomic mass Na=23.0u, Mg=24.0u)
4.
(a) Name a green house gas with molar mass 14g/mol and is known to extinguish fire.
(b) Name the elements present in this gas and write their valency
(c) Calculate the number of moles in 360 g of this gas sample
(d) Calculate the number of molecules in 88 g of this gas sample
(Given atomic mass of C =12u, O = 16u, No=6.022 x 1023 per mole)
5.
Calculate the following quantities in 5.6 g of nitrogen:(Atomic mass of N = 14u)
(a) Number of moles of N2
(b) Number of molecules of N2
Number of atoms of nitrogen
6.
Atomic mass of C-12 is 12 u.On the basis of mole concept, express 1 u into gram.
7.
Give the symbol and valency of the following polyatomic ions:
Ammonium, hydroxide, nitrate, carbonate, sulphate, sulphite, bicarbonate, phosphate.
8.
Give an account of existence of various elements and compounds.
9.
The drawbacks of Dalton's atomic theory of matter.
10.
50 g 0f 10% lead nitrate is mixed with 50g of 10% sodium chloride in a closed vessel.After reaction has taken place, it was found that 6.83 g of lead chloride was precipated.Besides, the reaction mixture contained 90g water and sodium nitrate.Calculate the amount of sodium nitrate formed.
1.
1 mole of aluminium oxide, Al2O3 = 2 x 27 + 3 x 16 = 102 u = 102 g
102 g Al2O3 has = 6.023 x 1023 Al2O3 molecules
0.051 g Al2O3 has = \(\frac { 6.023\times { 10 }^{ 23 } }{ 102 } \)
= 3.01 x 1020 Al2O3 molecuels
1 molecule of Al2O3 gives = 2Al+++ ions
Hence 0.051 g Al2O3 gives = 2 x 3.01 x 1020 Al+++ ions
=6.023 x 1023 aluminium ions.
2.
Molecular masses of H2 = 1 +1 = 2 u
Molecular masses of O2 = 16 +16 = 32 u
Molecular masses of Cl2 = 35.5 + 35.5 = 71 u
Molecular masses of CO2 = 12 + 32 = 44 u
Molecular masses of CH4 = 12 x 2 + 1 x 6 = 30 u
Molecular masses of C2H6 = 12 x 2 + 1 x 4 = 28 u
Molecular masses of NH3 = 1 x 14 + 1 x 3 = 17 u
Molecular masses of CH3OH = 1 x 12 + 1 x 3 + 1 x 16 + 1 x 1 = 32 u
3.
Number of atomes in 1 mole or 24 g Mg = 6.022 x 1023
Number of atoms in 6 g Mg = \(\frac { 6 }{ 24 } \times 6.022\times { 10 }^{ 23 }\)
= 2.5 x 1023 atoms
Now 6.022 x 1023 number of atoms in grams of sodium = 23 g
2.5 x 1023 number of atoms in grames of sodium = \(\frac { 23\times { 2.5\times 10 }^{ 23 } }{ 6.022\times { 10 }^{ 23 } } \)
= 9.548 x 10-1 g.
4.
(a) Carbon dioxide
(b) Elements: Carbon and oxygen.Valency of oxygen is -2 and carbon is +4 in CO
(c) Number of moles in 44 g CO = 1
Number of mole in 360 g CO = \(\frac { 360 }{ 44 } \) = 8.18 moles
(d) Number of molecules CO in 44 g = 6.022 x 1023
Number of molecxules of CO in 88 g = \(\frac { 88 }{ 44 } \times 6.022\times { 10 }^{ 23 }\)=12.044 x 1023
5.
(a)Molar mass of nitrogen = 14 g
5.6 gh of nitrogen = \(\frac { 5.6 }{ 14 } \)= 0.4 mole
(b) 28 g nitrogen = 6.0222 x 1023 molecules.
5.6 g of nitrogen = 2.15 x 1022 molecules
(c) 14 g of nitrogen = 6.0222 x 1023 atoms.
5.6 g of nitrogen = 4.30 x 1022 atoms.
6.
1 u = 1/12th of 1 atom of C-12
1 mole C-12 = 12 gram
12 gram C-12 = 6.022 x 1023 atoms
or 6.022 x 1023 atoms of C-12 = 12 grams
One atom of C-12 = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \)g
1 u = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \times \frac { 1 }{ 12 } \)
= 1.660302 x 10-24 gram.
7.
| Polyatomic ion | Symbol | Valency |
|---|---|---|
| Ammonium | (NH4)+ | +1 |
| hydroxide | (OH)- | -1 |
| nitrate | (NO3)- | -1 |
| carbonate | (CO3)2- | -2 |
| sulphate | (SO4)2- | -2 |
| sulphite | (SO3)2- | -2 |
| bicarbonate | (HCO3)- | -1 |
| phosphate | (PO4)3- | -3 |
8.
1. Metals exists as atomic crystals and do not form molecules.Generally, metals and other elements like carbon and silicon do not have single molecular structure but consists of a very large indefinite number of atoms bonded together.A form of carbon bonded with sixty atoms is called buckminsterfullerene
2. Non-metals exist as molecules containing one or more atoms.For example, argon exists as Ar and nitrogen as N2
3. Compounds containing non-metals only exist as molecules.For example, compound of nitrogen and hydrogen is a ammonia molecule.Compound of carbon and oxygen is a carbon dioxide molecule.
4. Compounds containing metals and non-metals exist as ions.For example, compound of sodium and chlorine consists of positivity charged sodium ions and negatively charged chloride ions.
9.
(i) According to Dalton's atomic theory, matter is invdivisible, i.e which cannot be divided.But now it is known that under special circumstances, atoms can be divided into still smaller particles called electrons, protons and neutrons.
(ii) Dalton's atomic theory fails to explain why substances like charcoal, graphite and diamond have different properties when all these substances are made up the same type of atoms, called carbon atoms.
(iii) Dalton's atomic theory postulated that all the atoms of the same element have exactly the same mass.It is now known that isotopes are atoms of the same element but have different masses.
(iv) It is known that some atoms called isobars have same masses but these belong to different elements.whereas Dalton's atomic theory says that atoms of different atoms have different masses.
10.
50 g of 10% lead nitrate means the solution contains 5 g lead nitrate and 45 g water.Similarly, 50 g of 10% sodium chloride means the solution contains 5 g sodium chloride and 45 g water.
Thus total contents before reaction = 5+5+90 = 100 g
After reaction, amount of water = 90 g
Amount of precipitate= 6.83 g
Since according to law of conservation of mass, the total mass of reaction mixture = 100 g
Amount of sodium nitrate = 100-90-6.83 = 3.17g
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