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9th Maths - Term 2 - Statistics Two Marks Questions

Published on: 21/09/2019

Term 2 - Statistics

Download Tamil Nadu 9th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

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Questions:

Generic 2

8 x 2 = 16

Find the mode of the given data: 3.1, 3.2, 3.3, 2.1, 1.3, 3.3, 3.1

In a research laboratory scientists treated 6 mice with lung cancer using medicine. Ten days, they measured the volume of the tumor of the tumor in each mouse given the results in the table

Mouse marking	1	2	3	4	5	6
Tumor Volume(mm)³	145	148	142	141	139	140

Find the mean

In a class test in mathematics, 10 students scored 75 marks,12 students scored 60 mark, 8 students scored 40 marks and 3 students scored 30 marks. Find the mean of their score.

The mean weight of 4 members of a family is 60 kg. Three of them have the weight 56kg, 68kg and 72 kg respectively. Find the weight of the fourth member.

In a week, temperature of a certain place is measured during winter are as follows 26^oC, 24^oC, 28^oC, 31^oC, 30^oC, 26^oC, 24^oC. Find the mean temperature of the week.

A set of numbers consists of five 4’s, four 5’s, nine 6’s, and six 9’s. What is the mode.

Find the mode for the set of values 17, 18, 20, 20, 21, 21, 22, 22.

In a rice mill, seven labours are receiving the daily wages of Rs. 500, Rs. 600, Rs. 600, Rs. 800, Rs. 800, Rs. 800 and Rs. 1000, find the modal wage

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Answers Key:

Generic 2

8 x 2 = 16

3.1, 3.2, 3.3, 2.1, 1.3, 3.3, 3.1
In this given data 3.1, 3.3 occurs twice
\(\therefore\) mode = 3.1 and 3.3 (bimodal)

\(\bar { x } =\frac { \Sigma x }{ n } =\frac { 145+148+142+141+139+140 }{ 6 } =\frac { 855 }{ 6 } \)
x = 142.5 mm²

Total number of students = 10 + 12 + 8 + 3 = 33
The total score of 33 students = 10\(\times\)75 +12 \(\times\) 60 + 8\(\times\)40 + 3\(\times\)30
= 750 + 720 + 320+90 = 1880
Mean of their score = \(\frac { Total\ Marks }{ number\ of\ students } =\frac { 188 }{ 33 } \)
= 56.96 or 57 approximately

\(\bar { x } =60kg\)
\(\bar { x } =\cfrac { \Sigma x }{ n } =\cfrac { 56+68+72+x }{ 4 } =60\)
196 + x = 260
x = 240-196
\(\therefore \) The weight of the fourth number = 44 kg

Mean \(\bar { x } =\cfrac { \Sigma x }{ n } \)
= \(\cfrac { 26+24+28+31+30+26+24 }{ 7 } =\cfrac { 189 }{ 7 } \)
Mean temperature of the week = 27⁰C