S = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)} 
n(S) = 36
(i) Probability of even number as the sum = \(\frac { 18 }{ 36 } =\frac { 1 }{ 2 } \)

Probability = \(\frac{2}{5}\).

A = {3, 6, 9, 12, 15, 18, 7, 14}
P(A) = \(\frac { 8 }{ 20 } =\frac { 2 }{ 5 } \).

A = {2, 3, 5, 7, 11, 13, 17, 19, 23}
P(A) = \(\frac{9}{25}\).

p(A) = 0.72
P(A') = 1 - 0.72 = 0.28

Total n(S) = 10,000
Defective n(A) = 25
Number of defective laptop is 25
Number of good laptop is = 10000 - 25 = 9975
Let A be the event of choosing a good laptop. n(A) = 9975
\(\mathrm{P}(\mathrm{A})=\frac{\mathrm{n}(\mathrm{A})}{\mathrm{n}(\mathrm{S})}=\frac{9975}{10000}\)
P(A) = 0.9975
Probability of getting a good laptop is 0.9975

(i) What is the probability that the spinner will not land on a multiple of 2?
(ii) What is the probability that the spinner will land on an odd number?

n(S) = 24
Red = n(R) = 3
Blue = n(B) = 5
Green= n(G) = 16
(i) Probability of picking a Blue ball =\(\frac { n(B) }{ n(S) } =\frac { 5 }{ 24 } \)
(ii) Probability of picking a Red ball =\(\frac { n(R) }{ n(S) } =\frac { 3 }{ 24 } =\frac { 1 }{ 8 } \)
(iii) Probability of picking a Green ball =\(\frac { n(G) }{ n(S) } =\frac { 16 }{ 24 } =\frac { 2 }{ 3 } \).

Faces of a dice (S) = {1, 2, 3, 4,5, 6}
n(S) = 6
Event of throwing an even number
A = {2, 4, 6}, n(A) = 3
∴ Probability of throwing an even number
P(A) = \(\frac { n(A) }{ n(S) } =\frac { 3 }{ 6 } =\frac { 1 }{ 2 } \).