9th Standard Syllabus & Materials
9th Standard
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NEW9th Standard
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NEW9th Standard
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NEW9th Standard
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NEW9th Standard
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Published on: 03/12/2019
Measurement
Download Tamil Nadu 9th Standard Science question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Science Test1.
_________is the unit of distance used to measure astronomical objects outside the solar system.
Parsec
km
cm
litre
2.
____________balance is used in lab.
Spring
Common
Physical
Digital
3.
To measure the diameter of a thin wire_________is used.
Screw gauge
Water gauge
Meter gauge
Wind gauge
4.
Which among the following is not a device to measure mass?
Spring balance
Beam balance
Physical balance
Digital balance
5.
Distance between Chennai and Kanyakumari can be found in
Kilometres
Metres
Centimetres
Millimetres
6.
Define length.
7.
In which part of the Vernier caliper is used to measure the internal diameter of a cylindrical pipe?
8.
Calculate the correct readings of the Vernier caliper L.C. 0.01 em Zero correction - Nil.
| S.No. | M.S.R | V.C | Observed Reading = M.S.R + (V.C x L.C) | Correct Reading |
| 1 | 3 | 4 | ||
| 2 | 3 | 7 |
9.
Convert: 104°F into Celsius scale.
10.
Can you find the diameter of a thin wire of length 2 m using the ruler from your instrument box?
11.
The Main scale reading is 3.8 Vernier scale coincidence = 5th division. No zero error. Find the length of the iron cylinder.
12.
While measuring the diameter of an iron nail using a screw gauge, the reading on the pitch scale is found to be 1.5 mm and the head scale reading is 20. If the least count is 0.01 mm and the zero error is + 0.05 mm, find the diameter of the iron nail.
13.
The mass of an object is 5 kg. What is its weight on the earth?
14.
How will you measure the least count of vernier caliper?
15.
What is the measuring unit of the thickness of a plastic carry bag?
16.
Find the diameter of a thin wire using screw gauge.
17.
Calculate the positive and negative error from the given figure
1.
(a)
Parsec
2.
(c)
Physical
3.
(a)
Screw gauge
4.
(a)
Spring balance
5.
(a)
Kilometres
6.
Length is defined as the distance between two points. The SI unit of length is metre.
7.
Upper jaws.
8.
| S.No. | M.S.R | V.C | Observed Reading = M.S.R + (V.C x L.C) | Correct Reading |
| 1 | 3 | 4 | 3 + (4 x 0.01) | 3.04 |
| 2 | 3 | 7 | 3 + (7 x 0.01) | 3.07 6.11 ____ 2 |
Correct reading = 3.55 cms.
9.
Celsius = (F – 32) × \(\frac{5}{9}\)= (104 - 32) ×\(\frac{5}{9}\) = 72 × \(\frac{5}{9}\) = 40°C.
10.
No. I cannot find the diameter of a thin wire by using the ruler.
11.
M.S. reading = 3.8 cm
V.S.R = 5th division
least count = 0.01 cm
Length = P.S.R + (V.S.C x L.C)
= 3.8 + (5 x 0.01) = 3.8 + 0.05 = 3.85
Length of the iron cylinder = 3.85 cm
12.
Given: P.S.R = 1.5 mm, H.S.R = 20 ; L.C = 0.01 mm
Z.E = + 0.05 mm ; Zero correction = - 0.05 mm
Diameter of iron nail = P.S.R + (H.S.R + L.C) + Z.C
= 1.5 + (20 x 0.01) - 0.05
= 1.5 + 0.20 - 0.05 = 1.65 mm
Diameter of iron nail = 1.65 mm
13.
Mass m = 5 kg
Acceleration due to gravity g = 9.8 ms-1
Weight W = m x g = 5 x 9.8 = 49 N
Therefore the weight of an object is 49 N
14.
The value is one smallest main scale division is divided by total number of vernier scale division is called the least count of vernier caliper.
\( \text { Least count } =\frac{\text { The value of one smallest main scale division }}{\text { Totalnumber of vernier scale division }}\)
\( \\ \text { L.C } =\frac{1 \mathrm{~mm}}{10}=0.1 \mathrm{~mm}=0.01 \mathrm{~cm}\)
15.
The measuring unit of the thickness of a plastic carry bag is micron.
16.
(i) Determine the pitch, the least count and the zero error of the screw gauge.
(ii) Place the wire between the two slides.
(iii) Rotate the head until the wire is held firmly but not tightly with the help of ratchet.
(iv) Note the P.S.R and H.S.R
(v) The diameter of the wire is given by
P.S.R + (H.S.C x L.C) ± Z.C,
(vi) Repeat the experiment for different portions of the wire.
(vii) Tabulate the readings.
(viii) The average of the last column reading gives the diameter of the wire.
| S.No. | P.S.R | H.S.C | H.S.C x L.C (mm) | Total Reading PSR + (HSC x LC) ± Z.C mm |
| 1. | ||||
| 2. | ||||
| 3. |
(ix) The average gives the correct reading.
17.
Case (a): Zero of the vernier scale and zero of the main scale are coinciding with each other. So there is no zero error.
Case (b): The zero of vernier scale is shifted to the right from the zero of the main scale. It is positive error. The 8th division of vernier scale coincides with one of the main scale divisions. So the positive error = (8×0.01cm) = 0.08 cm.
Case (c): The zero of vernier scale is shifted to the left from the zero of main scale. It is negative error. The 4th division of vernier scale (6th from backward) coincides with one of the main scale divisions. So the negative zero error = тАТ(6×0.01cm)= тАТ0.06 cm.
9th Standard Syllabus & Materials
9th Standard
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NEW9th Standard
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NEW9th Standard
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NEW9th Standard
TN 9роЖроорпН ро╡роХрпБрокрпНрокрпБ роЪроорпВроХ роЕро▒ро┐ро╡ро┐ропро▓рпН ро╡ро░ро▓ро╛ро▒рпБ - роЖроЪро┐роп роЖрокрпНрокро┐ро░ро┐роХрпНроХ роиро╛роЯрпБроХро│ро┐ро▓рпН роХро╛ро▓ройро┐ропро╛родро┐роХрпНроХроорпН роорпБроХрпНроХро┐ропрооро╛рой 2,3,&5 роородро┐рокрпНрокрпЖрогрпН ро╡ро┐ройро╛роХрпНроХро│рпН ро╡ро┐роЯрпИроХро│рпБроЯройрпН TN 9th Social Science HIS - Colonialism in Asia and Africa Important 1 Mark Questions with Answers 2,3,&5 Marks Questions with Answers.
Tamilnadu Stateboard 9th Standard Subjects
Tamilnadu Stateboard Standards
