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Published on: 30/08/2019
Number Systems
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Questions + Answers key
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1.
Divide \(8\sqrt { 15 } \) by \(2\sqrt { 3 } \)
2.
Find five rational numbers between 1 and 2.
3.
Find two irrational numbers between 0.1 and 0.12.
4.
If \(x={ \left( 2+\sqrt { 5 } \right) }^{ \frac { 1 }{ 2 } }+{ \left( 2-\sqrt { 5 } \right) }^{ \frac { 1 }{ 2 } }\) and \(y={ \left( 2+\sqrt { 5 } \right) }^{ \frac { 1 }{ 2 } }-{ \left( 2-\sqrt { 5 } \right) }^{ \frac { 1 }{ 2 } }\) , then evaluate \({ x }^{ 2 }+{ y }^{ 2 }\)
5.
Classify the following numbers as rational or irrational: \(\frac { 2\sqrt { 7 } }{ 7\sqrt { 7 } } \)
6.
If \({ 8 }^{ x }=\frac { 64 }{ { 2 }^{ x } } \) , then the value of x is
3
1
1/2
3/2
7.
The simplified form of \(\frac { { 13 }^{ \frac { 1 }{ 5 } } }{ { 13 }^{ \frac { 1 }{ 3 } } } \) is
\({ 13 }^{ \frac { 2 }{ 15 } }\)
\({ 13 }^{ \frac { 8 }{ 15 } }\)
\({ 13 }^{ \frac { 1 }{ 3 } }\)
\({ 13 }^{ \frac { 2 }{ 15 } }\)
8.
If \(\sqrt { x } \) is an irrational number, then x is:
rational
irrational
0
real
9.
Write the rationalizing factor of \(\frac{1}{\sqrt{50}}\) .
10.
Find the value of \(\sqrt[3]{625^{-2}}\)
11.
Is the product of two irrational numbers always an irrational number?
12.
Calculate the decimal which represents the fraction \(\frac{7}{8}\)
13.
Prove that: \({ \left( \frac { { x }^{ { a }^{ 2 } } }{ { x }^{ { b }^{ 2 } } } \right) }^{ \frac { 1 }{ a+b } }.{ \left( \frac { { x }^{ { b }^{ 2 } } }{ { x }^{ { c }^{ 2 } } } \right) }^{ \frac { 1 }{ b+c } }.{ \left( \frac { { x }^{ { c }^{ 2 } } }{ { x }^{ { a }^{ 2 } } } \right) }^{ \frac { 1 }{ c+a } }=1\)
1.
\(8 \sqrt{15} \div 2 \sqrt{3}=\frac{8 \sqrt{3} \times \sqrt{5}}{2 \sqrt{3}}=4 \sqrt{5}\)
2.
7/6,4/3,3/2,5/3 and 11/6
3.
The two irrational numbers between 0.1 and 0.12 can be taken as
0.1010010001...
0.11010010001...
4.
8
5.
\(\frac { 2\sqrt { 7 } }{ 7\sqrt { 7 } } \)=\(\frac { 2 }{ 7 } \) which is a rational number.
6.
(d)
3/2
7.
(d)
\({ 13 }^{ \frac { 2 }{ 15 } }\)
8.
(d)
real
9.
( )
\(\frac{1}{\sqrt{50}}=\frac{1}{\sqrt{5\times5\times2}}\)
=\(\frac{1}{5\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{10}\)
So, rationalizing factor is \(\sqrt{2}\)
10.
( )
\(\sqrt[3]{625^{-2}}\) = (625-2)1/4 = (625-2x1/4)
= (625-1/2)
= \((\frac{1}{625})^{1/2}=\frac{1}{25}\)
11.
( )
No, it may be rational or irrational.
12.
( )
\(\frac{7}{8}\)=0.875
13.
\(={ \left( { x }^{ { a }^{ 2 }-{ b }^{ 2 } } \right) }^{ \frac { 1 }{ a+b } }.{ \left( { x }^{ { b }^{ 2 }-{ c }^{ 2 } } \right) }^{ \frac { 1 }{ b+c } }.{ \left( { x }^{ { c }^{ 2 }-{ a }^{ 2 } } \right) }^{ \frac { 1 }{ c+a } }\)
\(={ x }^{ \frac { { a }^{ 2 }-{ b }^{ 2 } }{ a+b } }.{ x }^{ \frac { { b }^{ 2 }-{ c }^{ 2 } }{ a+b } }.{ x }^{ \frac { { c }^{ 2 }-{ a }^{ 2 } }{ c+a } }\)
\(={ x }^{ a-b }.{ x }^{ b-c }.{ x }^{ c-a }\)
\(={ x }^{ 0 }\)
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