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Published on: 28/08/2019
Lines and Angles
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1.
The sum of two supplementary angles is
\(90^{ 0 }\)
\(180^{ 0 }\)
\(360^{ 0 }\)
None of these
2.
The angles whose sum is \(180^{ 0 }\) are called
supplementary angles
complementary angles
alternate angles
corresponding angles
3.
The sum of two complimentary angles is
\(180^{ 0 }\)
\(360^{ 0 }\)
\(90^{ 0 }\)
None of these
4.
In how many points two intersecting lines intersect?
4
3
2
1
5.
The minimum number of points required to draw a line is
1
2
3
4
6.
In \(\triangle ABC,\angle A=\angle B/2=\angle C/6,\) then what will be the measurement of \(\angle A?\)
7.
In the figure below, if x,y and z are exterior angles of \(\triangle ABC\), then calculate the value of x+y+z.

8.
In the given fig., AB and CD are parallel to each other, then calculate the value of x/

9.
Write the angle which is one-fifth of its complement.
10.
In the figure below, AOB is a straight line. Calculate the measure of \(\angle COD\).

1.
(b)
\(180^{ 0 }\)
2.
Definition of complementary angles
3.
Definition of complementary angles
4.
(d)
1
5.
(b)
2
6.
( )
In \(\triangle ABC,\)
\(\angle A+\angle B+\angle C=180^o\)(By given conditions)
\(\Rightarrow \angle A+2\angle A+6\angle A=180^o\)
\(\Rightarrow 9\angle A=180^o\)
\(\Rightarrow \angle A=20^o\)
7.
( )
Since sum of all the exterior angles formed by producing the sides of a polygon is 360o
xo+yo+zo=360o
8.
( )
Let, l||AB||CD (by construction)

then, \(\angle OEF+\angle BOE=180^o\)
\(\angle O'EF+\angle DOE=180^o\)[Corresponding interior angles]
\(\angle OEF+\angle O'EF+120^o+140^o\)
=360o
\(\Rightarrow \angle OEO'=360^o-260^o\)
x=100o
9.
( )
Let the angle be x, then
By given condition, \(x=\frac{1}{5}(90^o-x)\Rightarrow6x=90^0\)
\(\Rightarrow x=15^0\)
10.
( )
\(\because\) x+20o+2x-20o+60o=180o (\(\because\) Straight line makes an angle of 180o)
\(\Rightarrow\) 3x=180o-60o=120o
\(\Rightarrow\) x=40o
Thus, \(\angle COD\)=2x-20o=80o-20o=60o
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