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Published on: 09/12/2019
Atoms and Molecules
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1.
Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.(Atomic mass of Al = 27u)
2.
Calculate the molecular masses of H2, O2, Cl2, CO2, CH4, C2H6, NH3, CH3OH
3.
If the molar mass of carbon is 12g, what is the mass of one atom of carbon in gram?
4.
Give the symbol and valency of the following polyatomic ions:
Ammonium, hydroxide, nitrate, carbonate, sulphate, sulphite, bicarbonate, phosphate.
5.
How will you explain the law of constant proportions on the basis of Dalton's atomic theory?
6.
What is meant by the term chemical formula?
7.
Name the ions in the following compounds:
Sodium fluoride, potassium bromide, calcium oxide, silver sulphide, magnesium oxide.
8.
What are ionic compounds?
9.
(i) One mole of carbon atom weighs 12 g.Find the mass in grams of one atom of carbon (Given C = 12u, No = 6.022 x 1023 per mole)
(ii) Calculate the mass of the following:
(a) 0.5 mole of N2 gas
(b) 0.2 mole of O-atoms
(c) 4 moles of aluminium atom
[Given, N = 14 u, 0 = 16 u, Al = 27 u,
Avogadro's number = 6.022 x 1023 per mole ]
10.
Verify by calculating that
(i) 5 moles of CO2 and 5 moles of H2O do not have the same mass.Atomic mass of carbon, oxygen and hydrogen are 12 u, 16 u, 14 u respectively.
(ii) 240 g of calcium and 240 g magnesium elements have a mole number ratio of 3 : 5.Atomic mass of calcium and magnesium are 40 u and 24 u respectively.
11.
Which one of the following compound is not made up of charged ions?
HCl
NaCl
MgCl2
CaO
12.
Molecules of the following element are made up of one atom of that element
Iron
Sodium
Helium
Chlorine
1.
1 mole of aluminium oxide, Al2O3 = 2 x 27 + 3 x 16 = 102 u = 102 g
102 g Al2O3 has = 6.023 x 1023 Al2O3 molecules
0.051 g Al2O3 has = \(\frac { 6.023\times { 10 }^{ 23 } }{ 102 } \)
= 3.01 x 1020 Al2O3 molecuels
1 molecule of Al2O3 gives = 2Al+++ ions
Hence 0.051 g Al2O3 gives = 2 x 3.01 x 1020 Al+++ ions
=6.023 x 1023 aluminium ions.
2.
Molecular masses of H2 = 1 +1 = 2 u
Molecular masses of O2 = 16 +16 = 32 u
Molecular masses of Cl2 = 35.5 + 35.5 = 71 u
Molecular masses of CO2 = 12 + 32 = 44 u
Molecular masses of CH4 = 12 x 2 + 1 x 6 = 30 u
Molecular masses of C2H6 = 12 x 2 + 1 x 4 = 28 u
Molecular masses of NH3 = 1 x 14 + 1 x 3 = 17 u
Molecular masses of CH3OH = 1 x 12 + 1 x 3 + 1 x 16 + 1 x 1 = 32 u
3.
1 u = 1/12th of 1 atom of C-12
1 mole C-12 = 12 gram
12 gram C-12 = 6.022 x 1023 atoms
or 6.022 x 1023 atoms of C-12 = 12 grams
One atom of C-12 = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \)g
1 u = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \times \frac { 1 }{ 12 } \)
= 1.660302 x 10-24 gram.
4.
| Polyatomic ion | Symbol | Valency |
|---|---|---|
| Ammonium | (NH4)+ | +1 |
| hydroxide | (OH)- | -1 |
| nitrate | (NO3)- | -1 |
| carbonate | (CO3)2- | -2 |
| sulphate | (SO4)2- | -2 |
| sulphite | (SO3)2- | -2 |
| bicarbonate | (HCO3)- | -1 |
| phosphate | (PO4)3- | -3 |
5.
According to dalton's atomic theory, each element consists of atoms which are similar have same weights.Further atoms of one element combine with atoms of another element to form compounds.Let us suppose that x atoms of element A combine with y atoms of element B and the compound formed is AxBy.If 'a' stands for the atomic mass of A and 'b' for that of b. then
Percentage of A in the compound=\(\frac { ax\times 100 }{ ax+by } \)
Percentage of B in the compound=\(\frac { by\times 100 }{ ax+by } \)
Now a and b are fixed x and y are also fixed whole numbers according to atomic theory.Therefore. percentage of A and B in the compound is also constant.This shows that the composition of various elements in a compound is also fixed.This is the law of constant proportion.
6.
The chemical formula of a compound is the symbolic representation of its composition.It gives the number and kinds of atoms which are chemically united in a given compound.For example, the chemical formula of hydrogen sulphide is HS.It tells that in hydrogen sulphide two hydrogen atoms and one sulphur atom are chemically united.
7.
Sodium fluoride - Sodium cation and fluoride anion
potassium bromide - Potassium cation and bromide anion
calcium oxide - Calcium cation and oxide anion
silver sulphide - Silver cation and sulphide anion
magnesium oxide - Magnesium cation and oxygen anion.
8.
Compounds containing charged species are known as ionic compounds.Such compounds are formed from combination of metals with non-meatls.For example, sodium chloride is an ionic compound.Its constituent particles charged sodium ions and negatively charged chloride ions.
9.
(i) 1 Mole of Carbon atom = 6.022 x 1023 atoms
6.022 x 1023 atoms of carbon weigh = 12 g
1 atom of carbon weighs = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \\ \)
= 1.99 x 10-23
(ii) (a) n = 0.5 mol; M = 14 x 2 = 28 g; m = ?
m = n x M = 0.5 x 28 = 14.0 g
(b) n = 0.2 mol; M = 16 g; m = ?
m = n x M = 0.2 x 16 = 3.2 g
(c) n = 4 mol; M = 27 g; m = ?
m = n x M = 4 x 27 = 108 g
10.
(i) Mass of 1 mole CO2 = 12 + 32 = 44 u
Mass of 5 moles CO2 = 44 x 5 = 220 u
Mass of 1 mole of H2O = 2 + 16 = 18 u
Mass of 5 moles of H2O = 5 x 18 = 90 u
(ii) 40 g calcium make = 1 mole
240 g calcium make = \(\frac { 240 }{ 40 } \) = 6 moles
24 g magnesium make = 1 mole
240 g magnesium make = \(\frac { 240 }{ 24 } \) = 10 moles
Ratio of 240 g calcium and 240 g magnesium in moles = \(\frac { 6 }{ 10 } \) or 3 : 5
11.
(a)
HCl
12.
(c)
Helium
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