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Published on: 20/09/2019
Atoms and Molecules
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1.
Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.(Atomic mass of Al = 27u)
2.
Which has more number of atoms, 100 grams of sodium or 100 grams of iron (Given, atomic mass of Na = 23 u, Fe = 56 u)?
3.
Which amongest the following has more number of atoms, 11.5 g of sodium or 15 g of calcium?How?(Given atomic mass of Na =23, ca=40)
4.
How many grames of Na will have the same number of atoms as in 6 grames of Mg?(Atomic mass Na=23.0u, Mg=24.0u)
5.
(a) Name a green house gas with molar mass 14g/mol and is known to extinguish fire.
(b) Name the elements present in this gas and write their valency
(c) Calculate the number of moles in 360 g of this gas sample
(d) Calculate the number of molecules in 88 g of this gas sample
(Given atomic mass of C =12u, O = 16u, No=6.022 x 1023 per mole)
6.
The mass of a single atom M is 3.05 x 10-23 g.What is its atomic weight?What would this element be? Check table for possible answers.
7.
Calculate the following quantities in 5.6 g of nitrogen:(Atomic mass of N = 14u)
(a) Number of moles of N2
(b) Number of molecules of N2
Number of atoms of nitrogen
8.
If the molar mass of carbon is 12g, what is the mass of one atom of carbon in gram?
9.
Atomic mass of C-12 is 12 u.On the basis of mole concept, express 1 u into gram.
10.
What is the utility of the mole concept?
11.
Give the symbol and valency of the following polyatomic ions:
Ammonium, hydroxide, nitrate, carbonate, sulphate, sulphite, bicarbonate, phosphate.
12.
The drawbacks of Dalton's atomic theory of matter.
13.
How will you explain the law of constant proportions on the basis of Dalton's atomic theory?
14.
50 g 0f 10% lead nitrate is mixed with 50g of 10% sodium chloride in a closed vessel.After reaction has taken place, it was found that 6.83 g of lead chloride was precipated.Besides, the reaction mixture contained 90g water and sodium nitrate.Calculate the amount of sodium nitrate formed.
1.
1 mole of aluminium oxide, Al2O3 = 2 x 27 + 3 x 16 = 102 u = 102 g
102 g Al2O3 has = 6.023 x 1023 Al2O3 molecules
0.051 g Al2O3 has = \(\frac { 6.023\times { 10 }^{ 23 } }{ 102 } \)
= 3.01 x 1020 Al2O3 molecuels
1 molecule of Al2O3 gives = 2Al+++ ions
Hence 0.051 g Al2O3 gives = 2 x 3.01 x 1020 Al+++ ions
=6.023 x 1023 aluminium ions.
2.
23 gram atomic unit or 23 gram sodium (1 mole) = 6.022 x 1023 atoms
100 gram atomic unit or 100 gram sodium (1 mole) = \(\frac { 6.022\times { 10 }^{ 23 }\times 100 }{ 23 } =2.617\times { 10 }^{ 24 }\)atoms
again 56 gram atomic unit or 56 grams iron (1 mole) = 6.022 x 1023 atoms
100 gram atomic unit or 100 grams iron = 1.075 x 1023 atoms
Thus 100 g of carbon has more atoms than 100g of iron.
3.
Number of atoms in 23 g of sodium =6.022 x 1023
Number of atoms in 11.5 g of sodium = \(\frac { 11.5 }{ 23 } \times 6.022\times { 10 }^{ 23 }\)
=3.011 x 1023 atoms
Number of atoms in 40 g of calcium = 6.022 x 1023
Number of atoms in 15 g of calcium = \(\frac { 6.022\times { 10 }^{ 23 }\times 15 }{ 40 } \)
=2.25 x 1023 atoms.
Therefore, 11.5g of sodium has more number of atoms than in 15g of calcium
4.
Number of atomes in 1 mole or 24 g Mg = 6.022 x 1023
Number of atoms in 6 g Mg = \(\frac { 6 }{ 24 } \times 6.022\times { 10 }^{ 23 }\)
= 2.5 x 1023 atoms
Now 6.022 x 1023 number of atoms in grams of sodium = 23 g
2.5 x 1023 number of atoms in grames of sodium = \(\frac { 23\times { 2.5\times 10 }^{ 23 } }{ 6.022\times { 10 }^{ 23 } } \)
= 9.548 x 10-1 g.
5.
(a) Carbon dioxide
(b) Elements: Carbon and oxygen.Valency of oxygen is -2 and carbon is +4 in CO
(c) Number of moles in 44 g CO = 1
Number of mole in 360 g CO = \(\frac { 360 }{ 44 } \) = 8.18 moles
(d) Number of molecules CO in 44 g = 6.022 x 1023
Number of molecxules of CO in 88 g = \(\frac { 88 }{ 44 } \times 6.022\times { 10 }^{ 23 }\)=12.044 x 1023
6.
1 mole = atomic mass = 6.022 x 1023 atoms
Now mass of one atom of M = 3.05 x 10-22
Now mass of 6.022 x 1023 atoms of M = 3.05 x 10-22 x 6.022 x 1023 g = 183.7 g
Mass of 1 mole or atomic mass of M = 183.7 g
This could be tungeten (W)
7.
(a)Molar mass of nitrogen = 14 g
5.6 gh of nitrogen = \(\frac { 5.6 }{ 14 } \)= 0.4 mole
(b) 28 g nitrogen = 6.0222 x 1023 molecules.
5.6 g of nitrogen = 2.15 x 1022 molecules
(c) 14 g of nitrogen = 6.0222 x 1023 atoms.
5.6 g of nitrogen = 4.30 x 1022 atoms.
8.
1 u = 1/12th of 1 atom of C-12
1 mole C-12 = 12 gram
12 gram C-12 = 6.022 x 1023 atoms
or 6.022 x 1023 atoms of C-12 = 12 grams
One atom of C-12 = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \)g
1 u = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \times \frac { 1 }{ 12 } \)
= 1.660302 x 10-24 gram.
9.
1 u = 1/12th of 1 atom of C-12
1 mole C-12 = 12 gram
12 gram C-12 = 6.022 x 1023 atoms
or 6.022 x 1023 atoms of C-12 = 12 grams
One atom of C-12 = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \)g
1 u = \(\frac { 12 }{ 6.022\times { 10 }^{ 23 } } \times \frac { 1 }{ 12 } \)
= 1.660302 x 10-24 gram.
10.
Utility of mole concept:
(i) Form the number of moles of a substance, we can calculate the number of elementary particles because the number of moles of a substance is directly proportional to the number of elements particles.
(ii) One mole of a gas occupies 22.4 litres at S.T.P
(iii) One mole of any gas under the same conditions of temperature and pressures occupies the same volume
(iv) One mole is equal to molecular mass in grams which is equal to 6.022 x 1023 atoms, molecules, ionsetc.Thus, we can calculate absolute masses of atoms and molecules.
11.
| Polyatomic ion | Symbol | Valency |
|---|---|---|
| Ammonium | (NH4)+ | +1 |
| hydroxide | (OH)- | -1 |
| nitrate | (NO3)- | -1 |
| carbonate | (CO3)2- | -2 |
| sulphate | (SO4)2- | -2 |
| sulphite | (SO3)2- | -2 |
| bicarbonate | (HCO3)- | -1 |
| phosphate | (PO4)3- | -3 |
12.
(i) According to Dalton's atomic theory, matter is invdivisible, i.e which cannot be divided.But now it is known that under special circumstances, atoms can be divided into still smaller particles called electrons, protons and neutrons.
(ii) Dalton's atomic theory fails to explain why substances like charcoal, graphite and diamond have different properties when all these substances are made up the same type of atoms, called carbon atoms.
(iii) Dalton's atomic theory postulated that all the atoms of the same element have exactly the same mass.It is now known that isotopes are atoms of the same element but have different masses.
(iv) It is known that some atoms called isobars have same masses but these belong to different elements.whereas Dalton's atomic theory says that atoms of different atoms have different masses.
13.
According to dalton's atomic theory, each element consists of atoms which are similar have same weights.Further atoms of one element combine with atoms of another element to form compounds.Let us suppose that x atoms of element A combine with y atoms of element B and the compound formed is AxBy.If 'a' stands for the atomic mass of A and 'b' for that of b. then
Percentage of A in the compound=\(\frac { ax\times 100 }{ ax+by } \)
Percentage of B in the compound=\(\frac { by\times 100 }{ ax+by } \)
Now a and b are fixed x and y are also fixed whole numbers according to atomic theory.Therefore. percentage of A and B in the compound is also constant.This shows that the composition of various elements in a compound is also fixed.This is the law of constant proportion.
14.
50 g of 10% lead nitrate means the solution contains 5 g lead nitrate and 45 g water.Similarly, 50 g of 10% sodium chloride means the solution contains 5 g sodium chloride and 45 g water.
Thus total contents before reaction = 5+5+90 = 100 g
After reaction, amount of water = 90 g
Amount of precipitate= 6.83 g
Since according to law of conservation of mass, the total mass of reaction mixture = 100 g
Amount of sodium nitrate = 100-90-6.83 = 3.17g
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