9th Standard Syllabus & Materials
9th Standard
TN 9th Tamil உள்ளத்தின் சீர் -கற்கண்டு (இலக்கணம்) - தொடர் இலக்கணம், ஆகுபெயர் Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உள்ளத்தின் சீர் -விரிவானம் (துணைப்பாடம்) - தாய்மைக்கு வறட்சி இல்லை! Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உள்ளத்தின் சீர் -கவிதை பேழை (செய்யுள்) - மார்கழி பெருவிழா Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உயிருக்கு வேர்-இலக்கணம் - பகுபத உறுப்பிலக்கணம் Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil அமுதென்று பேர் - இலக்கணம்-எழுத்து -அளபெடை Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil அமுதென்று பேர்-துணைப்பாடம் - ஆறாம்திணை Important Questions And Answers Study Material - QB365 Set A

Published on: 16/06/2021
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Questions + Answers key
Take MCQ Science Test1.
A racing car has a uniform acceleration of 4 ms-2. What distance it covers in 10 s after start?
2.
A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 ms-2 with what velocity will it strike the ground? After what time will it strike the ground?
3.
From the following Table, check the shape of the graph.
| Time (s) | 0 | 2 | 4 | 6 | 8 | 10 | 12 |
| Velocity(ms-1) | 0 | 20 | 40 | 40 | 40 | 20 | 0 |
4.
The adjacent diagram shows the velocity-time graph of a body. During what time interval is the motion of the body accelerated. Find the acceleration in the time interval mentioned in part 'a'. What is the distance travelled by the body in the time interval mentioned in part a?
1.
Acceleration (a) =4 m / s
Time (t) =10 second
distance (s) = ?
Initial velocity = 0
According to second equation of motion
\(s =u t+1 / 2 a t^{2} \)
\(=0+1 / 2 \times 4 \times(10)^{2} \)
\(=0+\frac{1}{\not 2} \times \not4^{2} \times 100 \)
= 0 + 200
= 200
Distance covers = 200 m.
2.
Height of a ball(s) =20 m
Acceleration (a)=10 m / s2
Initial velocity (u)=0
Final velocity (v)= ?
According to third equation of motion.
\(v^{2}=u^{2}+2\) as
\(=0+2 \times 10 \times 20 \)
\(v^{2} =0+400 \)
\(v =\sqrt{400} \)
\(v =\sqrt{20 \times 20} \)
\(v =20 \mathrm{~m} / \mathrm{s}^{2}\)
Velocity of ball strike the ground = 20 m / s2
According to first law of motion
v = u + at
20 = 0 + (10) x t
\(t =\frac{20}{10} \)
v =2 second
Time taken to strike the ground = 2 second
3.

4.
(a) = 4 seconds
(b) Acceleration = \(\frac { v-u }{ t } \)
= \(\frac { 30-0 }{ 7 } \) = 7.5 m/s2
(c) Displacement = Area of ΔABC
= \(\frac { 1 }{ 2 } \) x base x height
= \(\frac { 1 }{ 2 } \) x 4 x 30 =60 m

9th Standard Syllabus & Materials
9th Standard
TN 9th Tamil உள்ளத்தின் சீர் - திருக்குறள் Important Questions And Answers Study Material - QB365 Set A
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TN 9th Tamil உயிருக்கு வேர் - தண்ணீர் Important Questions And Answers Study Material - QB365 Set A
Tamilnadu Stateboard 9th Standard Subjects
Tamilnadu Stateboard Standards