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Published on: 14/09/2019
Number Systems
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1.
Evaluate: \(\frac { \sqrt [ 3 ]{ 2 } .{ 4 }^{ 3/2 } }{ { 128 }^{ 1/3 } } \)
2.
If x = 5 and y = 2, find the value of \((i)\quad \left( { x }^{ y }+{ y }^{ y } \right) \ (ii)\ { \left( { x }^{ y }+{ y }^{ y } \right) }^{ -1 }\)
3.
If \(\frac { 2+\sqrt { 3 } }{ 2-\sqrt { 3 } } +\frac { 2-\sqrt { 3 } }{ 2+\sqrt { 3 } } +\frac { \sqrt { 3 } -1 }{ \sqrt { 3 } +1 } =a+b\sqrt { 3 } \quad \) , find the rational numbers a and b.
4.
Classify the following numbers as rational or irrational: \(2\pi \)
5.
If \(a=\frac { \sqrt { 3 } +1 }{ \sqrt { 3 } -1 } \) and \(b=\frac { 1 }{ a } \) , find the value of \({ a }^{ 2 }+ab+{ b }^{ 2 }\)
6.
If \(a=\frac { \sqrt { 2 } +1 }{ \sqrt { 2 } -1 } \) and \(b=\frac { 1 }{ a } \), find the value of \({ a }^{ 2 }+{ b }^{ 2 }\)
7.
If \(x=3+2\sqrt { 2 } \) , find the value of \({ x }^{ 2 }+\frac { 1 }{ { x }^{ 2 } } \)
8.
Rationalize the denominator of \(\frac { 1 }{ \sqrt { 2 } } \)
9.
Simplify: (52)-7
10.
Simplify: 172.175
11.
Represent \(0.\overline { 237 } \) in the form p/q, where p and q are integers and \(q\neq 0\)
12.
Express \(0.\overline { 001 } \) as a rational number in the form p/q, where p and q are integers and \(q\neq 0\)
13.
Find two rational numbers between 0.1 and 0.2.
1.
2
2.
(i) 57
(ii) \(\frac { 1 }{ 3129 } \)
3.
a=16, b=-1
4.
2(\(\neq 0\)) is a rational number and \(\pi \) is an irrational number
\(2\pi \) is an irrational number.
The product of a non-zero rational number with an irrational number is irrational.
5.
15
6.
34
7.
34
8.
We want to write \(\frac { 1 }{ \sqrt { 2 } } \)as an equivalent expression in which the denominator is a rational number. We know that \(\sqrt{2} \cdot \sqrt{2} \) is rational. We also know that multiplying \(\frac{1}{\sqrt{2}} \text { by } \frac{\sqrt{2}}{\sqrt{2}}\) will give us an equivalent expression, since \(\frac{\sqrt{2}}{\sqrt{2}}=1\) . So, we put these two facts together to get
\(\frac{1}{\sqrt{2}}=\frac{1}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{2}\)
In this form, it is easy to locate \(\frac{1}{\sqrt{2}}\) on the number line. It is half way between 0 and \(\sqrt{2} \text {. }\)
9.
5-14
10.
177
11.
79/333
12.
1/999
13.
0.125, 0.15
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