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Published on: 14/09/2019
Atoms and Molecules
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1.
The most remarkable feature of Dalton's atomic theory was that of atomic mass.Since determining atomic mass of an individual atom was a difficult task, the relative atomic, masses were determined using the laws of chemical combinations and the compounds formed.In 1961, carbon-12 isotope was chosen as the standard reference for measuring atomic masses.It says that one atomic mass unit is a mass unit equal to exactly 1/12th the mass of one atom of carbon-12 Since experimentally t was observed that 3g cabon-12 combines with 4g of oxygen to form CO, further 4g sulphur combines with 4g oxygen to form SO2
(a) Calculate the atomic mass of sulphur.
(b) How was the concept of relative masses utilized in olden times?Was it successful?
2.
During the formation of ammonia, what mass of hydrogen gas would be required to react completely with 42 g of nitrogen gas?
3.
Calculate the number of molecules of sulphur (S8) present in 16 g of solid sulphur.
4.
A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen.Calculate the percentage composition of the compound by weight.
5.
16.26 mg of a sample of an element 'X' contains 1.66 x 1020 atoms.What is the atomic mass of the element X?
6.
Calculate the number of atoms in one grame of zinc (atomic mass of zinc is 65.37).Give the weight of 1 atom of zinc.
7.
Calculate the molecular mass of the following
(i) HNO3 (ii) CH3COOH
8.
The ratio of hydrogen and oxygen in water is 1:8 by mass, find out their ratio by number of atoms, in one molecule of water(Atomic mass: H = 1u, O=16u)
9.
How do you account for the fact that grame atomic mass or gram molecular mass of any substance contains the same number of particles?
10.
The chemical formula of chloride of metal 'M' is MCl.Write the chemical formula of its chloride, bicarbonate and sulphide.
11.
What are ionic compounds?
12.
What is an atom?
1.
(a) CCarbon combines with 4/3 times it mass of oxygen, so atomic mass of oxygen atom is \({4\over3}\times{12\over1}=16u\) Now since equal masses of sulphur and oxygen molecule combine to form SO2, atomic mass of sulphur is 16 x 2 = 32u.
(b) In earlier times, in the absence of weights, things were sold with reference to some other small substance.It was not successful because different people used different substance as reference material.
2.
To react with 14 g nitrogen, mass of hydrogen required = 3 g
Tor react with 42 g nitrogen, mass of hydrogen required = \(\frac { 3 }{ 14 } \times 42\) = 9g
3.
1 mole of S8 = 32 x 8 = 256 g
1 mole of S8 = 6.023 x 1023 molecules
256 g S8 has = 6.023 x 1023 S8 molecules
16 g S has = \(\frac { 6.023\times { 10 }^{ 23 } }{ 256 } \times 16=3.76\times { 10 }^{ 22 }\)molecules
4.
% of boron in the sample = \(\frac { 0.096 }{ 0.24 } \times 100\) = 40%
and % of oxygen in the sample = \(\frac { 0.144 }{ 0.24 } \times 100\)= 60 %
The sample of compound containes 40% boron and 60% oxygen by weight
5.
1 mole of an element 'X' contains 6.022 x 1023 atoms
Now weight of 1.66 x 1020 atoms = 16.26 x 10-3 g
Mass of 6.022 x 1023 atoms = \(\frac { 16.26\times { 10 }^{ -3 } }{ 1.66\times { 10 }^{ 20 } } \) x 6.02 x 1023 = 59 g
The atomic mass of element 'X' is 59 u
6.
Atomic mass of zinc = 65.37 g
65.37 g of zinc contains = 1 mole of zinc = 6.023 x 1023 atoms of Zn
1 g of zinc will contain = \(\frac { 6.023\times { 10 }^{ 23 } }{ 65.37 } \)= 9.21 x 1021 atoms.
1 atom of zinc = \(\frac { 1 }{ 9.21\times { 10 }^{ 21 } } \)= 1.08 x 10-22 g.
7.
(i) Molecular mass of HNO3 = 1 x 40 + 1 x 12 + 3 x 16 = 100u
(ii) Molecular mass of = 1 x 12 + 3 x 1 + x 12 + 1 x 16 + 1 x 16 + 1 x 1 = 60g
8.
When hydrogen is 1 g, amount of oxygen in water = 8g
Number of atoms of hydrogen in 1 g = 6.022 x 1023
Number of atoms of oxygen in 8 g = \(\frac { { 6.022\times 10 }^{ 23 } }{ 16 } \times 8\)
= 3.022 x 1023
Ratio of hydrogen and oxygen in water = \(\frac { { 6.022\times 10 }^{ 23 } }{ { 3.022\times 10 }^{ 23 } } \) = 2 : 1
9.
Atomic mass of any substance indicates the times it is heavier than 1/12th of C-12 atom.Now atomic mass of H atom is one u, it means that one C-12 atom is 12 times as heavy as one H atom or to say 1000 C-12 atoms are 12 times as heavy as 1000 h atoms or 6.022 x 1023 C-12 atoms are 12 times as heavy 6.022 x 1023 atoms.Since atomic mass of C-12 is 12u and that of H atoms is 1 u, it can be inferred that weight equal to atomic mass of C-12 or H-atom contains the same number of atoms.Thus, it can be shown that gram atomic mass or gram molecular mass of all substance have the same number, i,.e 6.022 x 1023 particles.
10.
Since M has a valancy of +1
Chemical formula of chloride of M = MCl
Chemical formula of bicarbonate of M = MHCO3
Chemical formula of sulphide of M = M2S
11.
Compounds containing charged species are known as ionic compounds.Such compounds are formed from combination of metals with non-meatls.For example, sodium chloride is an ionic compound.Its constituent particles charged sodium ions and negatively charged chloride ions.
12.
An atom is a building block of an element.It is very very small, so small that millions of atoms when stacked would hardly make a layer as thick as thin sheet of paper.The radius of an atom of hydrogen is 10-10 m or 10-1 nm, one molecule of water is 1 nm.Compared to it grain of sand is 10-4 m.
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