11th Standard Syllabus & Materials
11th Standard
Tamilnadu 11th Standard Tamil மொழி கலை -செய்யுள் - ஒவ்வொரு புல்லையும் Important Questions And Answers Study Material - QB365
NEW11th Standard
Tamilnadu 11th Standard Tamil கேடில் விழுச்செல்வம் - உரைநடை - தமிழகக் கல்வி வரலாறு Important Questions And Answers Study Material - QB365
NEW11th Standard
Tamilnadu 11th Standard Tamil பீடு பெற நில் - இலக்கணம் - பகுபத உறுப்புகள் Important Questions And Answers Study Material - QB365
NEW11th Standard
Tamilnadu 11th Standard Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set B
NEW11th Standard
Tamilnadu 11th Standard Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
Tamilnadu 11th Standard Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set B

Published on: 01/08/2018
Some of the important questions are prepared from this chapter Gaseous State. In this question paper, questions are prepared from the book back and creative question.
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Take MCQ Chemistry Test

1.
25g of each of the following gases are taken at 27°C and 600 mm Hg pressure. Which of these will have the least volume?
HBr
HCI
HF
HI
2.
The value of the gas constant R is ____________
0.082 dm3 atm.
0.987 cal mol-1K-1
8.3 J mol-1 K-1
8 erg mol-1 K-1
3.
The value of universal gas constant depends upon __________
Temperature of the gas
Volume of the gas
Number of moles of the gas
units of Pressure and volume.
4.
Equal weights of methane and oxygen are mixed in an empty container at 298 K. The fraction of total pressure exerted by oxygen is ___________
\(\frac { 1 }{ 3 } \)
\(\frac { 1 }{ 2 } \)
\(\frac { 2 }{ 3 } \)
\(\frac { 1 }{ 3 } \times 273\times 298\)
5.
When an ideal gas undergoes unrestrained expansion, no cooling occurs because the molecules _____________
are above inversion temperature
exert no attractive forces on each other
do work equal to the loss in kinetic energy
collide without loss of energy
6.
Which of the following is the correct expression for the equation of state of van der Waals gas?
\(\left( P+\frac { a }{ { n }^{ 2 }{ V }^{ 2 } } \right) (V-nb)=nRT\)
\(\left( P+\frac { na }{ { n }^{ 2 }{ V }^{ 2 } } \right) (V-nb)=nRT\)
\(\left( P+\frac { { an }^{ 2 } }{ { V }^{ 2 } } \right) (V-nb)=nRT\)
\(\left( \frac { P+{ n }^{ 2 }{ a }^{ 2 } }{ { V }^{ 2 } } \right) (V-ab)=nRT\)
7.
Write a short note on the consequence of Boyle's law. (or) Give the relationship between pressure and density
8.
What are ideal gases? In what way real gases differ from ideal gases.
9.
A balloon filled with air at room temperature and cooled to a much lower temperature can be used as a model for Charle's law.
10.
State Boyle's law.
11.
Define inversion temperature.
12.
Most aeroplanes cabins are artificially pressurized. Why?
13.
Define atmospheric pressure. What is its value?
14.
State Gay Lussac's law.
15.
Argon is an inert gas used in light bulbs to retard the vaporization of the tungsten filament. A certain light bulb containing argon at 1.2 atm and 18°C is heated to 85°C at constant volume. Calculate its final pressure in atm.
16.
A gas is enclosed in a room. The pressure, density, temperature and number of moles are p atm, g cm-3, t °C and n moles respectively. What will be the pressure, temperature, density and number of moles, in each compartment if room is partitioned into four equal compartments?
17.
Define pressure. Give its units.
18.
Define the terms isotherm, isobar and isochore.
19.
Define absolute zero. Is it possible to attain a further lower temperature? Comment on your answer.
20.
Give the mathematical expression that relates gas volume and moles.
21.
An inflated balloon has a volume of 275 mL, and contains 0.120 mole of air. As shown in fig a piece of dry ice weighing 1 g is placed in the balloon and its neck is tied. What is the volume of the balloon after dry ice (solid CO2) has vaporized? Assume pressure and temperature to remain constant.
1.
(d)
HI
2.
(c)
8.3 J mol-1 K-1
3.
(d)
units of Pressure and volume.
4.
(a)
\(\frac { 1 }{ 3 } \)
5.
(b)
exert no attractive forces on each other
6.
(c)
\(\left( P+\frac { { an }^{ 2 } }{ { V }^{ 2 } } \right) (V-nb)=nRT\)
7.
The pressure-density relationship can be derived from the Boyle's law as shown below.
P1V1 = P2V2 (Boyle's law)
\({ P }_{ 1 }\frac { m }{ { d }_{ 1 } } ={ P }_{ 2 }\frac { m }{ { d }_{ 2 } } \)
where "m" is the mass, d 1 and d2 are the densities of gases at pressure P1 and P2 .
\(\frac { { P }_{ 1 } }{ { d }_{ 1 } } =\frac { { P }_{ 2 } }{ { d }_{ 2 } } \)
In other words, the density of a gas is directly proportional to pressure.
8.
Gases which obey Boyle's Law and Charle's law or ideal gas equation PV = nRT are called ideal gases.
All gases whose behaviour is consistent with the assumption of kinetic theory of gases under all condition are called ideal gases.
| Ideal Gas | Real gas | |
|---|---|---|
| (i) | Ideal gases obey all gas laws under all conditions of temperature and pressure | Real obey gas law only at low pressures and high temperature. |
| (ii) | The volume occupied by a gas molecule is negligible when compared to the total volume of the gas. | The volume occupied by a gas molecule is not negligible when compared to the total volume of the gas. |
| (iii) | The attractive forces between the molecules are negligible | The force of attraction are not negligible at all temperatures and pressures. |
| (iv) | They obey the ideal gas equation: PV = nRT | They obey the Vander waal's equation: \(\left(P+\frac{n^{2} a}{V^{2}}\right)(V-n b)=n R T\) |
| (v) | The collision between the molecules are elastic | The collision between the molecules are not elastic |
| (vi) | No energy is involved during, the collision of the molecules of ideal gas | Collision of molecules in real gas have attractive energy |
9.
Charles law states that "At constant pressure, the volume of a given mass of an ideal gas is directly proportional to its temperature." According to Charles Law, if we were to take a balloon filled with air and increase the temperature of the air inside, the volume of air would increase causing the balloon to expand. This is caused by the heating of the molecules of air inside the balloon causing them to move rapidly. In the same manner if we cooled the balloon in a freezer, the volume of air decreases, making the balloon look partially deflated.
10.
At a given temperature the volume occupied by a fixed mass of a gas is inversely proportional to its pressure.
\(V\alpha \frac { 1 }{ P }\) at constant T& n.
Mathematical form: P1V1 = P2 V2 = K
11.
The temperature below which a gas obeys Joule - Thomson effect is called inversion temperature (Ti). This value is given using van der waals constants a and b.,
\(T_i=\frac{2a}{Rb}\)
12.
The pressure decreases with the increase in altitude because there are fewer molecules per unit volume of air. Above 9200 m (30,000 ft), for example, where most commercial aeroplanes fly, the pressure is so low that one could pass out for lack of oxygen. For this reason most aeroplanes cabins are artificially pressurized.
13.
(i) The pressure exerted on a unit area of Earth by the column of air above it is called atmospheric pressure.
(ii) The standard atmospheric pressure = 1 atm.
(iii) 1 atm = 760 mm Hg.
14.
At constant volume the pressure of a fixed mass of a gas is directly proportional to temperature, P ∝ T
or \(\frac{P}{T}\) = Constant k
If P1 and P2 are the pressures at temperatures T1 and T2 respectively, then from Gay Lussac's law
\(\frac { { P }_{ 1 } }{ { T }_{ 1 } } =\frac { { P }_{ 2 } }{ { T }_{ 2 } } \)
15.
Given data P1 = 1.2 atm
T1 = 18° C
T1 = 18 + 273 = 291 K
P2 = ?
T2 = 85° C
= 85 + 273 = 358 K
\(\frac { { P }_{ 1 } }{ { T }_{ 1 } } =\frac { { P }_{ 2 } }{ { T }_{ 2 } } \)
\({ P }_{ 2 }=\frac { { P }_{ 1 }{ T }_{ 2 } }{ { T }_{ 1 } } =\frac { 1.2\times 358 }{ 291 } \)
P2 = 1.48 atm
16.
Pressure in each compartment is same, p.
Temperature will remain same, t °C.
Density will remain same, d gcm-3.
The number of moles in each component will be, \(\frac { n }{ 4 } \) moles.
17.
It is defined as the force exerted by a gas on unit area of the wall
\(Pressure=\frac { Force }{ Area } \)
The SI unit of pressure is the Pascal (Pa), named after the French Mathematician and Physicist Blaise Pascal, and
1 Pa = 1 N m-2
1 N = 1 Kg m s-2
18.
(i) Isotherm:
The pressure-volume curve at constant temperature are known as isotherm.
(ii) Isobar:
The volume - temperature curve at constant pressure are known as isobar.
(iii) Isochore:
The pressure-temperature curve at constant volume are known as isochore.
19.
(i) The lowest hypothetical or imaginary temperature at which gases are supposed to occupy zero volume is called absolute zero.
(ii) Temperature below -273.15°C (absolute zero) is not possible, because it corresponds to negative volume, which is meaningless.
20.
According to Avogadro's hypothesis: V \(\alpha\) n
\(\therefore \frac{V_{1}}{n_{1}}=\frac{V_{2}}{n_{2}}=\text { constant }\)
V1 & n2 are the volume and number of moles of a gas and V2 & n2 are a different set of values of volume and number of moles of the same gas at same temperature and pressure.
21.
Given data V1 = 275 ml n1 = 0.120 moles
V2 = ?
\({ n }_{ 1 }=\frac { mass }{ molecular\ mass } =\frac { 1 }{ 44 } \)
Assuming pressure and temperature are constant According to Avogadro's hypothesis,
n2 = 0.227 moles
\(\frac { { V }_{ 1 } }{ { n }_{ 1 } } =\frac { { V }_{ 2 } }{ { n }_{ 2 } } \)
\({ V }_{ 2 }=\frac { { V }_{ 1 }{ n }_{ 2 } }{ { n }_{ 1 } } \)
\({ V }_{ 2 }=\frac { 275\times 0.0227 }{ 0.120 } \)
V2 = 52 moles
The volume of the balloon after dry ice has vaporized is V1 + V2 = 275 + 52 = 327 ml.
11th Standard Syllabus & Materials
11th Standard
Tamilnadu 11th Standard Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
Tamilnadu 11th Standard Tamil பீடு பெற நில் - உரைநடை - மலை இடப்பெயர்கள் : ஓர் ஆய்வு Important Questions And Answers Study Material - QB365 Set B
NEW11th Standard
Tamilnadu 11th Standard Tamil பீடு பெற நில் - உரைநடை - மலை இடப்பெயர்கள் : ஓர் ஆய்வு Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
Tamilnadu 11th Standard Tamil மாமழை போற்றுதும் - செய்யுள் - ஐங்குறுநூறு Important Questions And Answers Study Material - QB365 Set B
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Physics

Chemistry

Maths

Biology

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Physics

Chemistry

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Business Maths and Statistics

Computer Science

Accountancy

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History

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Commerce

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