9th Standard Syllabus & Materials
9th Standard
TN 9th Tamil உள்ளத்தின் சீர் -கற்கண்டு (இலக்கணம்) - தொடர் இலக்கணம், ஆகுபெயர் Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உள்ளத்தின் சீர் -விரிவானம் (துணைப்பாடம்) - தாய்மைக்கு வறட்சி இல்லை! Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உள்ளத்தின் சீர் -கவிதை பேழை (செய்யுள்) - மார்கழி பெருவிழா Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உயிருக்கு வேர்-இலக்கணம் - பகுபத உறுப்பிலக்கணம் Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil அமுதென்று பேர் - இலக்கணம்-எழுத்து -அளபெடை Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil அமுதென்று பேர்-துணைப்பாடம் - ஆறாம்திணை Important Questions And Answers Study Material - QB365 Set A

Published on: 31/08/2026
Download Tamil Nadu 9th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test

1.
Simplify: \( \left(8.41 \times 10^{4}\right) \div\left(4.3 \times 10^{5}\right) \)
2.
Simplify: (1.02 \(\times\) 1010) \(\times\) (1.20 \(\times\) 10-6)
3.
Simplify: (1.598 \(\times\) 1017) - (4.58 \(\times\) 1016)
4.
Simplify: (2.75 \(\times\)107)+(1.23 \(\times\) 108)
5.
Write the following numbers in decimal form:
(i) 3.459 \(\times\)106
(ii) 5.678 \(\times\) 104
(iii) 1.00005 \(\times\) 10-5
(iv) 2.530009 \(\times\)10-7
6.
Represent the following numbers in the scientific notation:
(i) 569430000000
(ii) 2000.57
(iii) 0.0000006000
(iv) 0.0009000002
7.
Given \(\sqrt{2}\) = 1.414, find the value of \(\frac { 8-5\sqrt { 2 } }{ 3-2\sqrt { 2 } } \) (to 3 places of decimals).
8.
If x = \(\sqrt{5}\) + 2, then find the value of \({ x }^{ 2 }+\frac { 1 }{ { x }^{ 2 } } \)
9.
Rationalise the denominator
(i) \(\frac { 1 }{ \sqrt { 50 } } \)
(ii) \(\frac { 5 }{ 3\sqrt { 5 } } \)
(iii) \(\frac { \sqrt { 75 } }{ \sqrt { 18 } } \)
(iv) \(\frac { 3\sqrt { 5 } }{ \sqrt { 6 } } \)
10.
Find the value of a and b if \(\frac { \sqrt { 7 } -2 }{ \sqrt { 7 } +2 } \) = a\(\sqrt{7}\) + b
11.
Rationalise the denominator and simplify \(\frac { \sqrt { 5 } }{ \sqrt { 6 } +2 } -\frac { \sqrt { 5 } }{ \sqrt { 6 } -2 } \)
12.
Rationalise the denominator and simplify \(\frac { 2\sqrt { 6 } -\sqrt { 5 } }{ 3\sqrt { 5 } -2\sqrt { 6 } } \)
13.
Rationalise the denominator and simplify \(\frac { \sqrt { 48 } +\sqrt { 32 } }{ \sqrt { 27 } -\sqrt { 18 } } \) .
1.
\( =\frac{8.41 \times 10^{4}}{4.3 \times 10^{5}} \\ =\frac{841 \times 10^{2}}{43 \times 10^{4}} \\ =19.558 \times 10^{-2} \\ =1.9558 \times 10^{-1} \)
2.
\( =1.02 \times 10^{10} \times 1.20 \times 10^{-3} \\ =1.224 \times 10^{7} \)
3.
\( =1.598 \times 10^{17}-4.58 \times 10^{15} \\ =\left(1.598-4.58 \times 10^{-2}\right) 10^{17} \\ =(1.598-0.0458) \times 10^{17} \\ =1.5522 \times 10^{17} \)
4.
\( \left(2.75 \times 10^{7}\right)+ \left(1.23 \times 10^{8}\right) \\ =\left(2.75 \times 10^{-1}+1.23\right) \times 10^{8} \\ =(0.275+1.23) \times 10^{8} \\ =1.505 \times 10^{8} \)
5.
(i) 3.459 \(\times\) 106 = 3459000
(ii) 5.678 \(\times\)104 = 56780
(iii) 1.00005 \(\times\) 10-5 = 0.0000100005
(iv) 2.530009 \(\times\) 10-7 = 0.0000002530009
6.
(i) 569430000000 = 5.6943 \(\times\)1011
(ii) 2000.57 = 2.00057 \(\times\) 103
(iii) 0.0000006000 = 6.0 \(\times\) 10-7
(iv) 0.0009000002 = 9.000002 \(\times\) 10-4
7.
\(\frac { 8-5\sqrt { 2 } }{ 3-2\sqrt { 2 } } =\frac{(8-5\sqrt{2})\times(3+2\sqrt{2})}{(3-2\sqrt{2})\times(+2\sqrt{2})}=\frac{24-15\sqrt{2}+16\sqrt{2}-10\times2}{3^2-(2\sqrt{2})^2}\)
=\(\frac{24+\sqrt{2}-20}{9-4\times2}=\frac{4+\sqrt{2}}{1}\) = 4 + 1.414 = 5.414
8.
\( x^{2} =(\sqrt{5}+2)^{2}=5+4+4 \sqrt{5}=9+4 \sqrt{5} \)
\(\frac{1}{x^{2}} =\frac{1}{9+4 \sqrt{5}} \)
\( =\frac{1}{9+4 \sqrt{5}} \times \frac{9-4 \sqrt{5}}{9-4 \sqrt{5}}=\frac{9-4 \sqrt{5}}{81-80} \)
\( ^{2}+\frac{1}{x^{2}} =9+4 \sqrt{5}+9-4 \sqrt{5} \)
\( =9+9+4 \sqrt{5}-4 \sqrt{5} \)
= 18
9.
(i) \(\frac{1}{\sqrt{50}}=\frac{1}{\sqrt{50}}\times\frac{\sqrt{50}}{\sqrt{50}}=\frac{\sqrt{50}}{\sqrt{50}}=\frac{\sqrt{5\times5\times2}}{5\times5\times2}=\frac{ ̶5̶\sqrt{2}}{ ̶5̶\times5\times2}=\frac{\sqrt{2}}{10}\)
(ii) \(\frac{5}{3\sqrt{5}}=\frac{5}{3\sqrt{5}}\times\frac{\sqrt{5}}{\sqrt{5}}=\frac{ ̶5̶\sqrt{5}}{3\times ̶5̶}=\frac{\sqrt{5}}{3}\)
(iii) \(\frac{\sqrt{75}}{\sqrt{18}}=\frac{\sqrt{3\times5\times5}}{\sqrt{3\times2\times3}}=\frac{5\sqrt{3}\times\sqrt{2}}{3\sqrt{2}\times\sqrt{2}}=\frac{5\sqrt{6}}{3\times2}=\frac{5\sqrt{6}}{6}\)
(iv) \(\frac{3\sqrt{5}}{\sqrt{6}}=\frac{3\sqrt{5}\times\sqrt{6}}{\sqrt{6}\times\sqrt{6}}=\frac{ ̶3̶\sqrt{30}}{ ̶6̶}=\frac{\sqrt{30}}{2}\)
10.
\(\frac { \sqrt { 7 } -2 }{ \sqrt { 7 } +2 } =a\sqrt{7}+b\)
L.H.S = \(\frac{\sqrt{7}-2\times\sqrt{7}-2}{\sqrt{7}+2\times\sqrt{7}-2}=\frac{(\sqrt{7}-2)^2}{\sqrt{7}^2-2^2}=\frac{\sqrt{7}^2-2\sqrt{7}\times2+2^2}{7-4}\)
=\(\frac{7-4\sqrt{7}+4}{3}=\frac{11-4\sqrt{7}}{3}=\frac{11}{3}-\frac{4\sqrt{7}}{3}\)
\(\frac{-4\sqrt{7}}{3}+\frac{11}{3}=a\sqrt{7}+b\)
ஃa √7=\(\frac{-4\sqrt{7}}{3}\)
a = \(\frac{-4}{3}\)
b = \(\frac{11}{3}\)
11.
\(\frac { \sqrt { 5 } }{ \sqrt { 6 } +2 } -\frac { \sqrt { 5 } }{ \sqrt { 6 } -2 } =\frac{\sqrt{5}(\sqrt{6}-2)-\sqrt{5}(\sqrt{6}+2)}{(\sqrt{6}+2)(\sqrt{6}-2)}\)
\(\frac{ ̶̶̶̶̶̶̶̶√̶3̶0̶-2\sqrt{5}- ̶̶̶̶̶̶̶̶√̶3̶0̶-2\sqrt{5}}{\sqrt{6}^2-2^2}=\frac{-4\sqrt{5}}{6-4}=\frac{ ̶4̶\sqrt{5}}{ ̶2̶}=-2\sqrt{5}\)
12.
\( \frac{2 \sqrt{6}-\sqrt{5}}{3 \sqrt{5}-2 \sqrt{6}} =\frac{2 \sqrt{6}-\sqrt{5}}{3 \sqrt{5}-2 \sqrt{6}} \times \frac{3 \sqrt{5}+2 \sqrt{6}}{3 \sqrt{5}-2 \sqrt{6}} \)
\( =\frac{6 \sqrt{30}+4 \times 6-3 \times 5-2 \sqrt{30}}{9 \times 5-4 \times 6} \)
\( =\frac{4 \sqrt{30}+24-15}{45-24}=\frac{9+4 \sqrt{30}}{21}\)
13.
\( =\frac{\sqrt{3 \times 16}+\sqrt{2 \times 16}}{\sqrt{3 \times 9}-\sqrt{2 \times 9}} \)
\( =\frac{\sqrt{3 \times 4^{2}}+\sqrt{2 \times 4^{2}}}{\sqrt{3 \times 3^{2}}-\sqrt{2 \times 3^{2}}} \)
\( =\frac{4 \sqrt{3}+4 \sqrt{2}}{3 \sqrt{3}-3 \sqrt{2}} \)
\( =\frac{4 \sqrt{3}+\sqrt{2}}{3 \sqrt{3}-\sqrt{2}}\)
\( =\frac{4(\sqrt{3}+\sqrt{2})}{3(\sqrt{3}-\sqrt{2})} \)
\( =\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}}\)
\( =\frac{4}{3}\left(\frac{(\sqrt{3}+\sqrt{2})^{2}}{(\sqrt{3})^{2}-(\sqrt{2})^{2}}\right)\)
\( =\frac{4}{3}\left(\frac{3+2 \sqrt{6}+2}{3-2}\right) \)
\( =\frac{4}{3}\left(\frac{5+2 \sqrt{6}}{1}\right)=\frac{4}{3}(5+2 \sqrt{6}) \)
9th Standard Syllabus & Materials
9th Standard
TN 9th Tamil உள்ளத்தின் சீர் - திருக்குறள் Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உள்ளத்தின் சீர் - மணிமேகலை Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உள்ளத்தின் சீர் - ஏறு தழுவுதல் Important Questions And Answers Study Material - QB365 Set A
NEW9th Standard
TN 9th Tamil உயிருக்கு வேர் - தண்ணீர் Important Questions And Answers Study Material - QB365 Set A
Tamilnadu Stateboard 9th Standard Subjects
Tamilnadu Stateboard Standards