Area of a triangle is equal to

In the figure, the area of parallelogram PQRS is:

In the given figure, if ABCD is a parallelogram, \(CF\bot AD\) and \(AE\bot DC\) If AB = 16 cm, AE = 4 cm and CF = 10 cm, the length of BC is:

If a triangle and a parallelogram are on same base and between same parallels, then the ratio of the area of the triangle to the area of the parallelogram is

In the figure, parallelogram ABCD and \(\Delta\)BCP are on the same base BC and between the same parallels. If ar(BCP) = 15 cm². Then ar(ABCD) equals:

In the figure, PQ || RS, ABCD is a parallelogram and AEB is a triangle. Area of the parallelogram ABCD is:

If the area of \(\Delta\)ABC is 800 cm² AD is a median, E is the midpoint of AD, F is the midpoint of AB, then the area of \(\Delta\)AEF (in cm²) is:

If the medians of a triangle ABC intersect each other at G, then area of \(\Delta\)AGB equals:

In the figure, ABCD is a parallelogram. If area (AOD) = 12 cm² then area (ABCD) is:

In the figure, BC = 2BE and area (\(\Delta\)ABC) = 60 cm², then ar (\(\Delta\)AEC) is:

In the figure, PQRS is a parallelogram with PQ = 12 cm, altitudes corresponding to PQ and SP are respectively 8 cm and 10 cm. Find SP.

In the figure, ar( \(\Delta\)ABE) = 50 cm². Find the area of the parallelogram ABCD. Give reasons.

In the figure, ABCD is a parallelogram. AB = 12 cm, DM = 6 cm and BN = 9 cm. Find the length of AD.

ABCD is a parallelogram with area 80 sq. cm. The diagonals AC and BD intersect at O. P is the midpoint of OA. Calculate ar(\(\Delta\) BOP)

In the given figure, ABCD is a \(BE\bot AD\)parallelogram. If BE = 14 cm and AD = 8 cm, find the area of  \(\Delta\)DBC.

In figure, AP || BQ || CR. Prove that ar(\(\Delta \)AQC) = ar(\(\Delta \)PBR).

Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar(\(\Delta \) AOD) = ar(\(\Delta \) BOC). Prove that ABCD is a trapezium.

ABCD is a quadrilateral and BD is one of its diagonals as shown in figure. Show that ABCD is a parallelogram and find its area.

 

ABCD is a parallelogram whose diagonals intersect at o. If P is any point on BO, prove that
(i) ar(\(\Delta \)ADO) =  ar(\(\Delta \) CDO)
(ii) ar(\(\Delta \)ABP) = ar(\(\Delta \) CBP)

\(\Delta \)ABC and \(\Delta \) ABD are two triangles on the same base AB. If line segment CD is bisected by AB at O, show that ar (\(\Delta \) ABC) = ar (\(\Delta \)ABD)