To check the number is divisible by 6 or not using nested if statement

To show the use of continue statement.

Rewrite the following program after removing the syntactical error(s), (if any). Underline each correction.
#include<iostream.h>
const int Multiple 3;
void main()
{
value = 15;
for( int Counter=1; Counter=<5; Counter++, value-=2)
if(value%Multiple==0)
       cout<<Value*Multiple;        
       cout<<endl;
else 
       cout<<Value+Multiple<<endl;
}

Write the following program execute successfully? If not, state the reason(s).
#include<stdio.h>
void main()
{
    int x, sum=0;
    cin<<n;
    for( X=1, x<100, x+=2)
     if x%2==0
       sum +=x;
cout>>"sum=">>sum;
}

Write a program to print the following output after inputting the value of n. The user should be prompted again for the value of n, if the inputted value does not lie between 1 to 6 do the inclusive.

                                 1
                          1     2     3
                    1     2    3     4    5
              1    2     3    4     5     6    7
              -    -     -      -      -      -     -
     1       2   -     -     -       -     -      -   (2n-1)

List the output of the program below.In other words, everytime there is a cout statement, list the values that will appear on the screen.
#include<iostream.h>
#include<conio.h>
void main()
{
 clrscr();
 for(int i=1;i<3;i++)
   for(int j=1;j<=5;j+=2)
      cout<<i<<"*"<<j<<"="<<i*j<<endl;
double a=1;
while(a<32)
      a*=2;
cout<<"a="<<a<<endl;
i=8,j=3;
int k=i/j;
double b=i/j;
double c=((double)i/(double)j);
cout<<"Now k="<<k<<", b="<<b<<", c="<<c<<endl;
getch();
}