Read the passage given below and answer the following questions:
When the mixture contains the three amine salts (1°, 2° and 3°) along with quaternary salt, it is distilled with KOH solution. The three amines distill, leaving the quaternary salt unchanged in the solution. Then the mixture of amines is separated by fractional distillation, Hinsbergs method and Hoffmann's method.

The following questions are multiple choice questions. Choose the most appropriate answer:
(i) Hinsberg reagent is

(ii) Primary amine with Hinsberg's reagent forms

(iii) To separate amines in a mixture Hoffmann's method is used. The Hoffmann's reagent is

(iv) 3^o amines with Hinsberg's reagent give

Read the passage given below and answer the following questions:
A mixture of two aromatic compounds (A) and (B) was separated by dissolving in chloroform followed by extraction with aqueous KOH solution. The organic layer containing compound (A), when heated with alcoholic solution of KOH produce C₇H₅N (C) associated with unpleasant odour.
The following questions are multiple choice questions. Choose the most appropriate answer:
The reaction of (A) with alcoholic solution of KOH to produce (C) of unpleasant odour is called

(ii) The alkaline aqueous layer (B) when heated with chloroform and then acidified give a mixture of isomeric compounds of molecular formula C₇H₆O₂. (B) is

(iii) In the chemical reaction, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}+\mathrm{CHCl}_{3}+3 \mathrm{KOH} \longrightarrow(A)+(B)+3 \mathrm{H}_{2} \mathrm{O},\) the compounds (A) and (B)  are respectively

(iv) Direct nitration of an aromatic compound (A) is not feasible because

Read the passage given below and answer the following questions:
The amines are basic in nature due to the presence of a lone pair of electron on N-atom of the -NH2 group, which it can donate to electron deficient compounds. Aliphatic amines are stronger bases than NH₃ because of the +1 effect of the alkyl groups. Greater the number of alkyl groups attached to N-atom, higher is the electron density on it and more will be the basicity. Thus, the order of basic nature of amines is expected to be 3° > 2° > 1°, however the observed order is 2° > 1° > 3°. This is explained on the basis of crowding on N-atom of the amine by alkyl groups which hinders the approach and bonding by a proton, consequently, the electron pair which is present on N is unavailable for donation and hence 3° amines are the weakest bases. Aromatic amines are weaker bases than ammonia and aliphatic amines. Electron -donating groups such as -CH₃ , -OCH₃ , etc. increase the basicity while electron-withdrawing substitutes such as -NO₂ , -CN, halogens, etc. decrease the basicity of amines. The effect of these substituents is more at p than at m-positions.
The following questions are multiple choice questions. Choose the most appropriate answer :
(i) Which one of the following is the strongest base in aqueous solution?

(ii) Which order of basicity is correct?

(iii) What ts the decreasing order of basicity of primary, secondary and tertiary ethylamines and NH₃?

(iv) Choose the correct statement.

Read the passage given below and answer the following questions:
Amines are alkyl or aryl derivatives of ammonia formed by replacement of one or more hydrogen atoms. Alkyl derivatives are called aliphatic amines and aryl derivatives are known as aromatic amines. The presence of aromatic amines can be identified by performing dye test. Aniline is the simplest example of aromatic amine. It undergoes electrophilic substitution reactions in which - NH₂ group strongly activates the aromatic ring through delocalisation oflone pair of electrons of N-atom. Aniline undergoes electrophilic substitution reactions. Ortho and para positions to the -NH₂ group become centres of high electrons density. Thus, -NH₂ group is ortho and para-directing and powerful activating group. The following questions are multiple choice questions.
Choose the most appropriate answer:
(i) Cyclohexylamine and aniline can be distinguished by

(ii) Which of the following compounds gives-dye test?

(iii) Oxidation of aniline with manganese dioxide and sulphuric acid produces

(iv) Aniline when treated with conc, HNO₃ and H₂SO₄ gives