In the figure, PQRS is a parallelogram with PQ = 12 cm, altitudes corresponding to PQ and SP are respectively 8 cm and 10 cm. Find SP.

2

(a)

In a parallelogram ABCD, AB = 8 cm. The altitudes corresponding to sides AB and AD are respectively 4 cm and 5 cm. Find measure of AD.

2

(a)

In the given figure, ABC and DBC are triangles on the same base and between parallel lines I and m. If AB = 3 cm, BC = 5 cm, \(\angle A=90°\), find area of \(\Delta \) DBC.

2

(a)

In the figure, ar( \(\Delta\)ABE) = 50 cm². Find the area of the parallelogram ABCD. Give reasons.

2

(a)

In the figure, ABCD is a parallelogram. AB = 12 cm, DM = 6 cm and BN = 9 cm. Find the length of AD.

2

(a)

If the area of parallelogram (shown in figure) is 80 cm² , then find area of \(\Delta \) ADP.

2

(a)

In the figure, ABCD is a parallelogram. P is a point on AB produced and \(DN\bot AB\) . If AB = 8 cm and DN = 3 cm. Find the area of \(\Delta \) CPD.

2

(a)

In the given figure:
(a) name the two triangles on the same base AB and between the same parallels.
(b) name a triangle and a parallelogram on the same base BC and between the same parallels.

2

(a)

ABCD is a parallelogram with area 80 sq. cm. The diagonals AC and BD intersect at O. P is the midpoint of OA. Calculate ar(\(\Delta\) BOP)

2

(a)

In the given figure, ABCD is a \(BE\bot AD\)parallelogram. If BE = 14 cm and AD = 8 cm, find the area of  \(\Delta\)DBC.

2

(a)

In the figure, PQRS is parallelogram with PQ=8 cm and ar(\(\Delta \)PXQ)=32 cm². Find the altitude of PQRS and hence its area.

2

(a)

ABCD is a quadrilateral and BD is one of its diagonals as shown in figure. Show that ABCD is a parallelogram and find its area.

2

(a)

ABCD is a parallelogram with area 80 sq. cm. The diagonals AC and BD intersect at O. P is the mid-point of OA. Calculator ar (\(\Delta\)BOP).

2

(a)

In the figure, PS||QR, Show that ar(\(\Delta \)ROS) = ar(\(\Delta \)POQ).

2

(a)

In given figure, ABCD is a parallelogram and BE\(\bot \)AD. If BE=14 cm and AD=8 cm, find the area of \(\Delta \)DBC.

2

(a)