If P(A\(\cup \)B) = 0.8 and P(A\(\cap \)B) = 0.3 then \(P(\bar { A } )+P(\bar { B } )\) =

(a)

0.3

(b)

0.5

(c)

0.7

(d)

0.9

If A and B are two events such that P(A) = \(\frac { 4 }{ 5 } \) and \(P(A\cap B)=\frac { 7 }{ 10 } \) then P(B/A) = 

(a)

\(\frac { 1 }{ 10 } \)

(b)

\(\frac { 1 }{ 8 } \)

(c)

\(\frac { 7 }{ 8 } \)

(d)

\(\frac { 17 }{ 20 } \)

If P(B)=\(\frac { 3 }{ 5 } \)P(A/B) = \(\frac { 1 }{ 2 } \) and \(P(A\cup B)=\frac { 4 }{ 5 } \), then P(A) is

(a)

\(\frac { 3 }{ 10 } \)

(b)

\(\frac { 1 }{ 2 } \)

(c)

\(\frac { 1 }{ 10 } \)

(d)

\(\frac { 3 }{ 5 } \)

If A and B are two independent events with P(A) = \(\frac { 3 }{ 5 } \) and P(B)=\(\frac { 4 }{ 9 } \) then \(P(\bar { A } \cap \bar { B } )\) = equals

(a)

\(\frac { 4 }{ 15 } \)

(b)

\(\frac { 8 }{ 45 } \)

(c)

\(\frac { 1 }{ 3 } \)

(d)

\(\frac { 2 }{ 9 } \)

Choose the incorrect pair:

(a)

A and B disjoint - P(A⋂B) = peA) + PCB

(b)

A and B independent - P(A⋂B) = p(A) P(B)

(c)

A and B disjoint - P(A⋂B) = 0

(d)

A and B independent - P(A/B) = P(B/A)