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11th Standard English Medium Maths Subject Two Dimensional Analytical Geometry Book Back 1 Mark Questions with Solution Part - I

11th Standard

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Maths

Time : 01:00:00 Hrs
Total Marks : 10

    1 Marks

    10 x 1 = 10
  1. The equation of the locus of the point whose distance from y-axis is half the distance from origin is

    (a)

    x+ 3y= 0

    (b)

    x2- 3y= 0

    (c)

    3x2+ y= 0

    (d)

    3x2- y= 0

  2. Which of the following equation is the locus of (at2, 2at)

    (a)

    \(\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\)

    (b)

    \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\)

    (c)

    x+ y= a2

    (d)

    y= 4ax

  3. Which of the following point lie on the locus of 3x2+ 3y2- 8x - 12y + 17 = 0

    (a)

    (0, 0)

    (b)

    (-2, 3)

    (c)

    (1, 2)

    (d)

    (0, -1)

  4. If the point (8, -5) lies on the locus \(\frac{x^2}{16}-\frac{y^2}{25}=k\), then the value of k is

    (a)

    0

    (b)

    1

    (c)

    2

    (d)

    3

  5. The slope of the line which makes an angle 45o with the line 3x- y = -5 are:

    (a)

    1, -1

    (b)

    \(\frac{1}{2},-2\)

    (c)

    \(1,\frac{1}{2}\)

    (d)

    \(2,-\frac{1}{2}\)

  6. Equation of the straight line that forms an isosceles triangle with coordinate axes in the I-quadrant with perimeter 4 + 2\(\sqrt{2}\) is

    (a)

    x + y + 2 = 0

    (b)

    x + y - 2 = 0

    (c)

    \(x+y-\sqrt{2}=0\)

    (d)

    \(x+y+\sqrt{2}=0\)

  7. The coordinates of the four vertices of a quadrilateral are (-2, 4), (-1, 2), (1, 2) and (2, 4) taken in order. The equation of the line passing through the vertex (-1, 2) and dividing the quadrilateral in the equal areas is

    (a)

    x + 1 = 0

    (b)

    x + y = 1

    (c)

    x + y + 3 = 0

    (d)

    x - y + 3 = 0

  8. The intercepts of the perpendicular bisector of the line segment joining (1, 2) and (3, 4) with coordinate axes are

    (a)

    5, -5

    (b)

    5, 5

    (c)

    5, 3

    (d)

    5, -4

  9. The equation of the line with slope 2 and the length of the perpendicular from the origin equal to \(\sqrt5\) is

    (a)

    x - 2y = \(\sqrt5\)

    (b)

    2x - y =\(\sqrt5\)

    (c)

    2x - y = 5

    (d)

    x - 2y - 5 = 0

  10. If the equation of the base opposite to the vertex (2, 3) of an equilateral triangle is x + y = 2, then the length of a side is

    (a)

    \(\sqrt{\frac{3}{2}}\)

    (b)

    6

    (c)

    \(\sqrt{6}\)

    (d)

    \(3\sqrt{2}\)

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