#### 11th Standard Physics English Medium Free Online Test Creative One Mark Questions with Answer Key - Part Five

11th Standard

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Physics

Time : 00:10:00 Hrs
Total Marks : 10

10 x 1 = 10
1. Least count of screw gauge:

(a)

0.01 mm

(b)

0.01 cm

(c)

0.1 mm

(d)

1cm

2. Resultant of two vectors which are parallel to each other and are in the same direction is obtained by of vectors.

(a)

(b)

subtraction

(c)

multiplication

(d)

division

3. A car runs at a constant speed on a circular track of radius 100 m, taking 62.8 seconds for every circular lap. The average velocity and average speed for each circular lap respectively is

(a)

10m\s,0

(b)

0,0

(c)

0,10m/s

(d)

10m/s,10m/s

4. The angle between parallel vectors is

(a)

0o

(b)

90o

(c)

180o

(d)

0 (or) 180o

5. Inertia is that property of a body by virtue of which the body is:

(a)

unable to change by itself the state o frest

(b)

unable to change by itself the state of uniform motion

(c)

unable to change by itself the direction of motion

(d)

unable to change by itself the state of rest and ofunifonn linear motion

6. Rate of change of momentum of an object is equal to

(a)

acceleration

(b)

work done

(c)

force

(d)

impulse

7. You lift a heavy book from the floor of the room and keep it in the book shelf having a height 2m. In this process you take 5 seconds. The work done by you will depend upon:

(a)

mass of the book and time taken

(b)

weight of the book and height of the book-shelf

(c)

height of the book-shelf and time taken

(d)

mass of the book, height of the book-shelf and time taken

8. 1 erg is equivalent to

(a)

10-7 J

(b)

1.6 x 10-19 J

(c)

4.186 J

(d)

3.6 x 10-6J

9. If a solid sphere and solid cylinder of same mass and radius rotate about their own axis the moment of inertia will be greater for:

(a)

solid sphere

(b)

solid cylinder

(c)

both (a) & (b)

(d)

equal both

10. Two practicals of equal mass m go round a circle of radius R under the action of their mutual gravitational attraction. the speed of each particle is

(a)

$\frac { 1 }{ 2R } \sqrt { \frac { 1 }{ Gm } }$

(b)

$\frac { Gm }{ 2R }$

(c)

$\frac { 1 }{ 2 } \sqrt { \frac { GM }{ R } }$

(d)

$\sqrt { \frac { 4GM }{ R } }$