#### 11th Standard Physics English Medium Free Online Test Creative One Mark Questions with Answer Key - Part Four

11th Standard

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Physics

Time : 00:10:00 Hrs
Total Marks : 10

10 x 1 = 10
1. How many AU present in one light year?

(a)

6.30 x 104m

(b)

9.46 x 1015m

(c)

6.2 x 102m

(d)

9.4 x 1016m

2. If $\bar A$and $\bar B$ are two vectors, $\bar A.\bar B=\bar A\times\bar B$ then resultant vector is:

(a)

A+B

(b)

A-B

(c)

$\sqrt {A^2+B^2}$

(d)

$\sqrt {A^2+B^2+\sqrt{2}AB}$

3. A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. what should be the speed of the throw so that more than two bails are in the sky at any time ? (Given g=9.8m/s2)

(a)

more than 19.6 m/s

(b)

at least 9.8 m/s

(c)

any speed less than 19.6m/s

(d)

only with speed 19.6 m/s

4. The position vector of a particle is $\vec r=4t^2\hat i+2t\hat j+3\hat k$ . The speed of the particle at t = 5s is

(a)

42 ms-1

(b)

3 s

(c)

3 ms-1

(d)

40 ms-1

5. Unit of momentum

(a)

kg ms-2

(b)

kg ms-1

(c)

M L T-2

(d)

M L T-1

6. The law of conservation of energy always. holds good when:

(a)

a body moves down a rough plane

(b)

two electrically charged particles collide

(c)

two bodies collide

(d)

a body moves (or rolls) down a smooth plane

7. For inelastic collision co-efficient of restitution is

(a)

0

(b)

1

(c)

0 < e < 1

(d)

$\infty$

8. A wheel of moment of inertia 4 x 10-3 kgm2 is making 10 revolutions per second. The torque required to stop it in 5 seconds is

(a)

$2\pi\times 10^{-3} Nm$

(b)

$8\pi \times 10^{-3} Nm$

(c)

$16\pi \times 10^{-3} Nm$

(d)

$8\times 10^{-3}Nm$

9. The velocity of the rolling object on inclined plane at the bottom of inclined plane is

(a)

$\sqrt { \frac { 1+\frac { { k }^{ 2 } }{ { R }^{ 2 } } }{ gsin^{ 2 }\theta } }$.

(b)

$\sqrt { \frac { 2gh }{ 1+\frac { { k }^{ 2 } }{ { R }^{ 2 } } } }$.

(c)

$\sqrt { \frac { 2h\left( 1+\frac { { k }^{ 2 } }{ { R }^{ 2 } } \right) }{ gsin^{ 2 }\theta } }$.

(d)

$\sqrt { \frac { 2h\left( 1+\frac { { k }^{ 2 } }{ { R }^{ 2 } } \right) }{ gsin^{ 2 }\theta } }$.

10. While negotiating a circular level road a cyclist has to bend by an angle θ from vertical to stay in an equilibrium is

(a)

$tan \theta=\frac{rg}{r^{2}}$

(b)

$\theta=tan^{-1} (\frac{v^{2}}{rg})$

(c)

$\theta = sin^{-1}(\frac{rg}{r^{2}})$

(d)

zero