T1 - Numbers English Medium Free Online Test 1 Mark Questions with Answer Key 2020 - 2021

6th Standard

    Reg.No. :
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Maths

Time : 00:10:00 Hrs
Total Marks : 10

    Part A

    10 x 1 = 10
  1. The successor of 10 million is

    (a)

    1000001

    (b)

    10000001

    (c)

    9999999

    (d)

    100001

  2. The expanded form of the number 6,70,905 is

    (a)

    6 \(\times\) 10000 + 7 \(\times\) 1000 + 9 \(\times\) 100 + 5 \(\times\) 1

    (b)

    6 \(\times\) 10000 + 7 \(\times\) 1000 + 0 \(\times\) 100 + 9 \(\times\) 100 + 0 \(\times\) 10 + 5 \(\times\) 1

    (c)

    6 \(\times\) 1000000 + 7 \(\times\) 10000 + 0 \(\times\) 1000 + 9 \(\times\) 100 + 0 \(\times\) 10 + 5 \(\times\) 1

    (d)

    6 \(\times\) 100000 + 7 \(\times\) 10000 + 0 \(\times\) 1000 + 9 \(\times\) 100 + 0 \(\times\) 10 + 5 \(\times\) 1

  3. The Arabian Sea has an area of 1491000 square miles. This area lies between which two numbers?

    (a)

    1489000 and 1492540

    (b)

    1489000 and 1490540

    (c)

    1490000 and 1490100

    (d)

    1480000 and 1490000

  4. The value of 3 + 5 − 7 \(\times\) 1 is ________.

    (a)

    5

    (b)

    7

    (c)

    8

    (d)

    1

  5. Use BIDMAS and put the correct operator in the box. 2 \(\Box\) 6 - 12 \(\div \) (4 + 2) = 10

    (a)

    +

    (b)

    -

    (c)

    \(\times\)

    (d)

    \(\div \)

  6. The estimation to the nearest hundred of 76812 is

    (a)

    77000

    (b)

    76000

    (c)

    76800

    (d)

    76900

  7. The estimated difference of 167826 and 2765 rounded off to the nearest thousand is

    (a)

    180000

    (b)

    165000

    (c)

    140000

    (d)

    155000

  8. \(\frac { 59 }{ 1 } \) is

    (a)

    1

    (b)

    0

    (c)

    \(\frac { 1 }{ 59 } \)

    (d)

    59

  9. The whole number that does not have a predecessor is

    (a)

    10

    (b)

    0

    (c)

    1

    (d)

    none of these

  10. Which of the following is not true?

    (a)

    (4237 + 5498) + 3439 = 4237 + (5498 + 3439)

    (b)

    (4237 \(\times\) 5498) \(\times\) 3439= 4237 \(\times\) (5498 \(\times\) 3439)

    (c)

    4237 + 5498 \(\times\) 3439 = (4237 + 5498) \(\times\) 3439

    (d)

    4237 \(\times\) (5498 + 3439) = (4237 \(\times\) 5498) + (4237 \(\times\) 3439)

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