New ! Maths MCQ Practise Tests



Inverse Trigonometric Functions 1 Mark Creative Question Paper With Answer Key

12th Standard

    Reg.No. :
  •  
  •  
  •  
  •  
  •  
  •  

Maths

Time : 00:15:00 Hrs
Total Marks : 15

    Multiple Choice Question

    15 x 1 = 15
  1. If \(\alpha ={ tan }^{ -1 }\left( tan\frac { 5\pi }{ 4 } \right) \) and \(\beta ={ tan }^{ -1 }\left( -tan\frac { 2\pi }{ 3 } \right) \) then ___________

    (a)

    \(4\alpha =3\beta \quad \)

    (b)

    \(3\alpha =4\beta \)

    (c)

    \(\alpha -\beta =\frac { 7\pi }{ 12 } \)

    (d)

    none

  2. The number of real solutions of the equation \(\sqrt { 1+cos2x } ={ 2sin }^{ -1 }\left( sinx \right) ,-\pi  is ___________

    (a)

    0

    (b)

    1

    (c)

    2

    (d)

    infinte

  3. If \(\alpha ={ tan }^{ -1 }\left( \frac { \sqrt { 3 } }{ 2y-x } \right) ,\beta ={ tan }^{ -1 }\left( \frac { 2x-y }{ \sqrt { 3y } } \right) \) then \(\alpha -\beta \) __________

    (a)

    \(\frac { \pi }{ 6 } \)

    (b)

    \(\frac { \pi }{ 3 } \)

    (c)

    \(\frac { \pi }{ 2 } \)

    (d)

    \(\frac { -\pi }{ 3 } \)

  4. \({ tan }^{ -1 }\left( \frac { 1 }{ 4 } \right) +{ tan }^{ -1 }\left( \frac { 2 }{ 11 } \right) \) = ____________

    (a)

    0

    (b)

    \(\frac { 1 }{ 2 } \)

    (c)

    -1

    (d)

    none

  5. If tan-1(3) + tan-1(x) = tan-1(8) then x = ____________ 

    (a)

    5

    (b)

    \(\frac { 1 }{ 5 } \)

    (c)

    \(\frac { 5 }{ 14 } \)

    (d)

    \(\frac { 14 }{ 5 } \)

  6. The value of \({ cos }^{ -1 }\left( \cos\cfrac { 5\pi }{ 3 } \right) +sin^{ -1 }\left( \sin\cfrac{5\pi }{ 3 } \right) \) is ______________ 

    (a)

    \(\cfrac { \pi }{ 2 } \)

    (b)

    \(\cfrac { 5\pi }{ 3 } \)

    (c)

    \(\cfrac { 10\pi }{ 3 } \)

    (d)

    0

  7. \(sin\left\{ 2{ cos }^{ -1 }\left( \frac { -3 }{ 5 } \right) \right\} =\) __________

    (a)

    \(\frac { 6 }{ 15 } \)

    (b)

    \(\frac { 24 }{ 25 } \)

    (c)

    \(\frac { 4 }{ 5 } \)

    (d)

    \(\frac { -24 }{ 25 } \)

  8. If \(4{ cos }^{ -1 }x+{ sin }^{ -1 }x=\pi \) then x is _____________

    (a)

    \(\frac { 3 }{ 2 } \)

    (b)

    \(\frac { 1 }{ \sqrt { 2 } } \)

    (c)

    \(\frac { \sqrt { 3 } }{ 2 } \)

    (d)

    \(\frac { 2 }{ \sqrt { 3 } } \)

  9. If \({ tan }^{ -1 }\left( \frac { x+1 }{ x-1 } \right) +{ tan }^{ -1 }\left( \frac { x-1 }{ x } \right) ={ tan }^{ -1 }\left( -7 \right) \) then x is ___________

    (a)

    0

    (b)

    -2

    (c)

    1

    (d)

    2

  10. If \({ cos }^{ -1 }x>x>{ sin }^{ -1 }x\) then _________

    (a)

    \(\cfrac { 1 }{ \sqrt { 2 } }

    (b)

    \(0\le x<\frac { 1 }{ \sqrt { 2 } } \)

    (c)

    \(-1\le x<\frac { 1 }{ \sqrt { 2 } } \)

    (d)

    x>0

  11. In a \(\Delta ABC\)  if C is a right angle, then  \({ tan }^{ -1 }\left( \frac { a }{ b+c } \right) +{ tan }^{ -1 }\left( \frac { b }{ c+a } \right) =\) ________

    (a)

    \(\frac { \pi }{ 3 } \)

    (b)

    \(\frac { \pi }{ 4 } \)

    (c)

    \(\frac { 5\pi }{ 2 } \)

    (d)

    \(\frac { \pi }{ 6 } \)

  12. \(cot\left( \frac { \pi }{ 4 } -{ cot }^{ -1 }3 \right) \)

    (a)

    7

    (b)

    6

    (c)

    5

    (d)

    none

  13. If tan-1(cot \(\theta\)) = 2\(\theta\), then\(\theta\) = _____________

    (a)

    \(\pm 3\)

    (b)

    \(\pm \frac { \pi }{ 4 } \)

    (c)

    \(\pm \frac { \pi }{ 6 } \)

    (d)

    none

  14. The domain of cos-1(x2 - 4) is______

    (a)

    [3, 5]

    (b)

    [-1, 1]

    (c)

    \(\left[ -\sqrt { 5 } ,-\sqrt { 3 } \right] \cup \left[ \sqrt { 3 } ,\sqrt { 5 } \right] \)

    (d)

    [0, 1]

  15. The value of tan \(\left( { cos }^{ -1 }\frac { 3 }{ 5 } +{ tan }^{ -1 }\frac { 1 }{ 4 } \right) \) is ______

    (a)

    \(\frac { 19 }{ 8 } \)

    (b)

    \(\frac { 8 }{ 19 } \)

    (c)

    \(\frac { 19 }{ 12 } \)

    (d)

    \(\frac { 3 }{ 4 } \)

*****************************************

Reviews & Comments about 12th Standard Maths English Medium - Inverse Trigonometric Functions 1 Mark Creative Question Paper and Answer Key 2022 - 2023

Write your Comment